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Komok [63]
4 years ago
6

Does anyone knows the answer?

Mathematics
1 answer:
Elena L [17]4 years ago
3 0

Answer:

yeeeeeeeeeeeeeeeeessssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

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allochka39001 [22]
........................................
7 0
4 years ago
Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
Which expression represents this word phrase?
irakobra [83]
I'm pretty sure the answer is D. 6x + 5.  I hope this helps.
4 0
3 years ago
Read 2 more answers
A rock show is being televised the lead singer who is 75 inches tall is 15 inches tall on a TV monitor the image of the bass pla
VladimirAG [237]
75 : 15 = x : 13
15 x = 75 · 13
15 x = 975
x = 975 : 15
x = 65
Answer:
The bass player is 65 inches tall.
6 0
4 years ago
Write an equation of the line in slope-intercept form
Elena L [17]
Y=-5/2x-1

hope this helps
4 0
3 years ago
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