Answer:
a = 94
b = -66√3
Step-by-step explanation:
Given z = 
![(-1-i\sqrt{3})^6=[(-1-i\sqrt{3})^3]^2](https://tex.z-dn.net/?f=%28-1-i%5Csqrt%7B3%7D%29%5E6%3D%5B%28-1-i%5Csqrt%7B3%7D%29%5E3%5D%5E2)
![=[-(1+i\sqrt{3})^3]^{2}](https://tex.z-dn.net/?f=%3D%5B-%281%2Bi%5Csqrt%7B3%7D%29%5E3%5D%5E%7B2%7D)
![=[(1+i\sqrt{3})^3]^2](https://tex.z-dn.net/?f=%3D%5B%281%2Bi%5Csqrt%7B3%7D%29%5E3%5D%5E2)
![=[(1)^3+(i\sqrt{3})^3+3(1)^2(i\sqrt{3})+3(1)(i\sqrt{3})^2]^2](https://tex.z-dn.net/?f=%3D%5B%281%29%5E3%2B%28i%5Csqrt%7B3%7D%29%5E3%2B3%281%29%5E2%28i%5Csqrt%7B3%7D%29%2B3%281%29%28i%5Csqrt%7B3%7D%29%5E2%5D%5E2)
[(a + b)³ = a³ + b³ + 3a²b + 3ab²]
= [1 + 3i² + 3i√3 + 9i²]²
= [1 - 3 + 3i√3 - 9]²
= [-11 + 3i√3]²
= (11)² -2(3i√3)(11) + (3i√3)²
= 121 - 66i√3 + 27i²
= 121 - 66i√3 - 27
= (94 - 66i√3)
Comparing it with (a + bi),
a = 94 and b = -66√3
32,667 that will be in numbers
Answer:
A
Step-by-step explanation:
For the sequence, the defining formula is given as;
an = Previous term + 9
So a2 will be -5 + 9 = 4
a3 will be 4 + 9 = 13
a4 will be 13 + 9 = 22
a5 will be 22 + 9 = 31
So the sequence of numbers will be;
-5, 4 , 13 , 22 , 31
Answer:
Step-by-step explanation:
If you are talking about a die with 6 faces, then 16 isn't possible. 12 is the highest possible number.
If you are talking about some other kind of die, you have to specify it.
I'm going to assume you made a mistake and meant 6.
There are 5 ways to get six
3 - 3
4 - 2
2 - 4
5 - 1
1 - 5
There are 36 ways of throwing 2 dice.
So the probability = 5/36 = 0.1389
If you really did mean 16 then the probability = 0
Answer:
-34.64
Step-by-step explanation:
-20.3-14.34
-34.64
