Alright remember, if any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
k+1=0
k-5=0
Set the first factor equal to 0 and solve
k=-1
Set the next factor equal to 0 and solve
k=5
The final solution is all the values that make (k+1)(k-5)=0 true.
k=-1, 5
Hope this helped you out :)
I suppose you want to know such number. Since we have a two digit number consisting of two consecutive integers, the only possible numbers are:
Since we sorted all the cases out, we simply have to check which one satisfies the requirement. For each number, we'll write four times the the sum of its digits, and add 6, hoping to get the original number.
So, the answer is 34.
Answer:
25/36
Step-by-step explanation:
Use the top top, bottom bottom method.
5*5 = 25
6*6 = 36
Write i in trigonometric form. Since |i| = 1 and arg(i) = π/2, we have
i = exp(i π/2) = cos(π/2) + i sin(π/2)
By DeMoivre's theorem,
i² = exp(i π/2)² = exp(i π) = cos(π) + i sin(π)
and it follows that i² = -1 since cos(π) = -1 and sin(π) = 0.
Answer:
c = 7√2
Step-by-step explanation:
Apply pythagorean theorem to find the third side.
Thus, c² = a² + b²
where, c is the third side and a and b are the other sides.
Plug in the values
c² = 8² + (√34)²
c² = 64 + 34
c² = 98
c = √98
c = √(49 * 2)
c = 7√2
