The value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27
<h3>How to evaluate the expression?</h3>
The expression is given as:
3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two
Rewrite properly as:
[3² * 3⁻⁵]/[5⁻²]
Apply the negative exponent law of indices
So, we have
[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]
Apply the exponent law of indices
[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]
This gives
[3² * 3⁻⁵]/[5⁻²] = 25/27
Hence, the value of the expression given as [3² * 3⁻⁵]/[5⁻²] is 25/27
Read more about expressions at:
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Answer:
The point estimate for this problem is 0.48.
Step-by-step explanation:
We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.
A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".
<em>Let </em>
<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>
<u></u>
<u>Now, point estimate (</u><u>) is calculated as;</u>
where, X = number of students who answered yes = 1,344
n = number of students surveyed = 2,800
So, Point estimate () = 
= <u>0.48 or 48%</u>
Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
4/5 x 2/8 = 0.2 or 8/40 = 4/20 = 2/10 = 1/5
