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denpristay [2]
3 years ago
12

Need to find x please.

Mathematics
1 answer:
frez [133]3 years ago
7 0

Answer:

4 MIUSE 90 PLUSE 22

Step-by-step explanation:

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(A-6) to the power of 2 turned into equation
weeeeeb [17]
1) acknowledge the rule that anything that’s outside of the bracket applies to EVERYTHING inside of the bracket
2)apply the rule: (A-6)^2
3 0
3 years ago
6+2[x+8]+3x+11+x help plzzzzz
Alex787 [66]
6+2(x+8)+3x+11+x
First you have to expand the brackets:
6+2x+16+3x+11+x
Now you group like terms (terms with the same or no variable):
2x+3x+x+11+16+6
And finally, combine like terms:
6x+33

Hope this helps :)
4 0
3 years ago
Assume that the random variable X is normally distributed, with mean 60 and standard deviation 16. Compute the probability P(X &
elixir [45]

Answer:

P(X < 80) = 0.89435.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 60, \sigma = 16

P(X < 80)

This is the pvalue of Z when X = 80. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 60}{16}

Z = 1.25

Z = 1.25 has a pvalue of 0.89435.

So

P(X < 80) = 0.89435.

5 0
3 years ago
Find two points on the line to be graphed 2y+16=0
yarga [219]
Y=-8 so any x with the coordinate -8 for y i guess. 
4 0
3 years ago
Sam has traveled 33 miles and knows that 55% of his trip is complete.How many total miles is Sam's trip?
ahrayia [7]
60 miles in total.
to find percentages, you divide the part by the whole, so 33/60 = .55, which you then move the decimal over two places and read as a percentage
5 0
3 years ago
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