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sashaice [31]
3 years ago
9

Find the distance between points (1, 2) and (5, 9). Show all work.

Mathematics
1 answer:
vekshin13 years ago
7 0

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:


\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}


"d" represents the distance and coordinates are expressed as follows: (x, y)


Let's go to the calculations.


\mathsf{d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}\\\\ \mathsf{d=\sqrt{(5-1)^2+(9-2)^2}}\\\\ \mathsf{d=\sqrt{(4)^2+(7)^2}}\\\\ \mathsf{d=\sqrt{16+49}}\\\\ \mathsf{d=\sqrt{65}}\\\\ \mathsf{d=8.06225774829854...}\\\\ \underline{\mathsf{d\approxeq8.06}}


The answer is 8.06 uc.

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Answer:

  789 m²

Step-by-step explanation:

Consider the cross section created by a vertical plane through the apex of the pyramid and bisecting opposite sides. The cross section is an isosceles triangle with base 20 m and height 17 m. One side of this triangle is the slant height of the face of the pyramid.

The side of the triangle above can be found using the Pythagorean theorem. A median from the apex of the triangle will divide it into two right triangles, each with a base of 10 m and a height of 17 m. Then the hypotenuse is ...

  s² = (10 m)² +(17 m)² = 389 m²

  s = √389 m ≈ 19.723 m . . . . . slant height of one triangular face

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The area of one triangular face is ...

  A = (1/2)sb

where s is the slant height above, and b is the 20 m base of the face of the pyramid. There are 4 of these faces, so the total area is ...

  total lateral area = 4A = 4(1/2)sb = 2sb = 2(19.723 m)(20 m)

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7 0
3 years ago
What is the absolute value equation for this graph
Svetlanka [38]

Answer:

y = -|x - 2| + 4

Step-by-step explanation:

The parent function of the absolute value function is y = |x|. There is a negative reflection in the x-axis, a horizontal translation of 2 units right, and a vertical translation of 4 units up.

4 0
3 years ago
Find x Help ASAP ASAP
Blizzard [7]

the given figure is a rhombus, so it's area =

\frac{1}{2}  \times \: d1 \times d2

where, d1 and d2 are diagonals of the rhombus,

and since, the diagnonals of rhombus bisects each other, the values of their diagonals are

(2 × x) and (2 × 15) =》2x and 30 respectively,

so, by finding the area using the given diagonals and equating it with the real area, we get :

=》

\frac{1}{2}  \times 2x \times 30 = 300

=》

x \times 30 = 300

=》

x =  \frac{300}{30}

=》

x = 10

so,

value of x = 10 units

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3 years ago
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Ne4ueva [31]

Answer:

No solution

Step-by-step explanation:

6x - 2(3x - 4)

Distribute;

6x - 6x + 8

0 ≠ 8

3 0
3 years ago
Find the inequality represented by the graph​
aleksklad [387]

Answer:

y>=-2x-5 is the answer. Just to be sure, check the points of the equation with an ordered pair shaded that should reveal if this answer is valid.

Step-by-step explanation:

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