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sergij07 [2.7K]
3 years ago
7

What is the value of - 13/ 7 + 6/ 7​

Mathematics
2 answers:
dybincka [34]3 years ago
5 0

Answer:

-1

Step-by-step explanation:

To add fractions, find the LCD (Least Common Denominator) and then combine.

Vanyuwa [196]3 years ago
3 0
Ans: -1

-13/7 + 6/7

-7/7

-1
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A roller coaster's height from the ground is modeled by r(t) = 4sin(4t)+25 where t is time in minutes. A Ferris wheel's height f
GuDViN [60]

Un cateto, en geometría, es cualquiera de los dos lados menores de un triángulo rectángulo, los que conforman el ángulo recto. El lado de mayor medida se denomina hipotenusa –el que es opuesto al ángulo recto. La denominación de catetos e hipotenusa se aplica a los lados de los triángulos rectángulos exclusivamente.

3 0
3 years ago
The slide is 4 meters due west of the tire swing and 3 meters due south of the monkey bars. What is the distance between the tir
padilas [110]

Answer:

The distance between the tire swing and the monkey bars = 5 m

Step-by-step explanation:

Given:

Distance between tire swing and the slide = 4 m

Distance between monkey bars and slide = 3 m

We have to find the distance between tire swing and the monkey bars.

Let the distance be "h" meters.

From the diagram we can see that when they are arranged they form a right angled triangle.

Where the distance we have to find is the hypotenuse of the triangle.

Using Pythagoras formula:

⇒ (hypotenuse)^2 = (base)^2 + (perpendicular)^2

Plugging the values:

⇒ (hypotenuse)^2 = (base)^2 + (perpendicular)^2

⇒ h^2=b^2+p^2

⇒ h=\sqrt{b^2+p^2}

⇒ h=\sqrt{(4)^2+(3)^2}

⇒ h=\sqrt{16+9}

⇒ h=\sqrt{25}

⇒ h=5 m

So,

The distance between the tire swing and the monkey bars = 5 m

6 0
3 years ago
What is the scientific notation of 0.0121
jek_recluse [69]
You move to the right, so the exponent is gonna be negative.
1.21 * 10-²
6 0
4 years ago
You have a chess board as pictured, with squares numbered 1 through 64. You also have a huge change jar with an unlimited number
ANEK [815]

Answer:

(a) 512 dimes

(b)D(n) = 2^{n-1}

(c) 9.22337 x 10¹⁸ dimes

(d) 9.22337 x 10¹² km

(e) roughly 61,489.13 times longer than the distance from the earth to the sun.

Step-by-step explanation:

b. Starting with 1 dime in the first square, if the number of dimes per each square is the double of the previous square, the general equation for the number of dimes in each square 'n' can be found by:

D(1) = 1\\D(2) = 2^1\\D(3) = 2^2\\D(4) = 2^3\\D(n) = 2^{n-1}

a. On the 10th square:

D(10) = 2^{10-1}\\D(10) = 512\ dimes

c. On the 64th square:

D(64) = 2^{64-1}\\D(10) = 9.22337 *10^{18}\ dimes

d. If a dime is 1 mm thick, the 64th pile will be:

h= 9.22337*10^{18}*0.0001\ m\\h= 9.22337*10^{15}\ m\\h= 9.22337*10^{12}\ km

e. The ratio between the height of the last pile (h) to the distance from the earth to the sun is:

R=\frac{9.22337*10^{12}\ km}{150,000,000\ km}\\ R=61,489.13

The height of the last pile is roughly 61,489.13 times longer than the distance from the earth to the sun.

5 0
3 years ago
Subtract the fractions and reduce to lowest terms. 1/ 3 − 1/ 12
Fofino [41]

3/ 4+2/ 5=1 3/ 20

3 forths + 2 fifths = 1 and 3 twentyiths

Hope i helped! :)

5 0
4 years ago
Read 2 more answers
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