Consider the function
, which has derivative
.
The linear approximation of
for some value
within a neighborhood of
is given by
Let
. Then
can be estimated to be
![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since
for
, it follows that
must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function
. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
Answer:
A B and C are true
Step-by-step explanation:
Answer:
6x > x + 20,
x > 4
or
X belongs to a set of real numbers [0, +infinity)
Step-by-step explanation:
6x > x + 20
5x > 20
x > 4
Part A:
From the graph, it seems that the lines intersect at (3,-1)... This seems to be the solution...
Part B:
g(x) is a negative line, and the slope is 2 (from rise/run). Y int. = 5. So, the equation is -2x+5. Plug in some numbers for this; say 1 and 2. The coordinates would be (1,3) and (2,1).
Part C:
The 2 graphs seem to intersect at (0,5), so this is the solution...
ALL of this is based on only looking at the graph, which is no better than drawing lines on the sand.. For example, the y intercept for g(x) could be 4.9 or 5.1, and I don't know the equation for f(x)... Based on the info I have, gave my best answers..
Hope this helps..
154 divided by 2
Answer = x = 77
