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3 years ago

Can I get help on #22?!

Mathematics

2 answers:

hjlf3 years ago

8 0

thirty-five million eight hundred twenty-three thousand seven hundred seventy-five

Valentin [98]3 years ago

8 0

I agree with the other guys answer

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What is 4x + 27 = 10x - 33 multi-step equations

rusak2 [61]

4x+27=10x−33 then,4x+27−10x=10x−33−10x next,−6x+27=−33−6x+27−27=−33−27 next,−6x=−60 then,−6x−6=−60−6 finally,x=10

7 0

4 years ago

Ax-b=c solve for b A- b= -ax-c B- b=ax+c C- b= -ax+c D- b=ax-c

Alex

Ax - b = c....subtract ax from both sides
-b = -ax + c <==
or it could also have been b = ax - c (but that ones not there)

6 0

3 years ago

The four-member math team at Pecanridge Middle School is chosen from the math club, which has three girls and five boys. How man

cestrela7 [59]

Answer:

$Total\ Selection = 30\ ways$

Step-by-step explanation:

Given

Girls = 3

Boys = 5

Required

How many ways can 2 boys and girls be chosen?

The keyword in the question is chosen;

This implies combination and will be calculated as thus;

$Selection =\ ^nC_r = \frac{n!}{(n-r)!r!}$

For Boys;

n = 5 and r = 2

$Selection =\ ^5C_2$

$Selection = \frac{5!}{(5-2)!2!}$

$Selection = \frac{5!}{3!2!}$

$Selection = \frac{5 * 4 * 3!}{3!*2 * 1}$

$Selection = \frac{20}{2}$

$Selection = 10$

For Girls;

n = 3 and r = 2

$Selection =\ ^3C_2$

$Selection = \frac{3!}{(3-2)!2!}$

$Selection = \frac{3!}{1!2!}$

$Selection = \frac{3 * 2!}{1 *2!}$

$Selection = \frac{3}{1}$

$Selection = 3$

Total Selection is calculated as thus;

$Total\ Selection = Boys\ Selection * Girls\ Selection$

$Total\ Selection = 10 * 3$

$Total\ Selection = 30\ ways$

5 0

4 years ago

I need serious help with some geometry who can help me?

Amanda [17]

I can try. Is there a picture/question?

5 0

3 years ago

3x/4 + 3 = 20 yyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Yanka [14]

3x/4+3=20
<=> 0.75x +3 =20
<=> 0.75x = 17
<=> x = 68/3

3 0

3 years ago