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lions [1.4K]
3 years ago
12

Find the missing length round to the nearest tenth if necessary​

Mathematics
1 answer:
Alexus [3.1K]3 years ago
6 0

Answer:

I believe your answer would be 11, but it could also be 10.7. but rounding to the nearest tenth it would be 11 so go for 11.

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The equation of the line that goes through the point (−10,8) and (−3,-4) can be written in the form y=mx+b
Y_Kistochka [10]

Answer:

m is -12/7 and b is -64/7

Step-by-step explanation:

Use rise over run (change in y / change in x) to find the slope, m:

(-4 - 8) / (-3 + 10)

= -12/7

So, m is -12/7.

Plug in this value and a point into y = mx + b, then solve for b:

y = mx + b

-4 = -12/7(-3) + b

-4 = 36/7 + b

-64/7 = b

So, m is -12/7 and b is -64/7

8 0
3 years ago
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frutty [35]
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fiasKO [112]

Answer:

c) -6

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3 0
3 years ago
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Oduvanchick [21]

Answer:

2

Step-by-step explanation:

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5 0
4 years ago
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The figure below shows a rectangle ABCD having diagonals AC and DB:
Kisachek [45]

Answer: C is the correct statement " In ΔADC and ΔBCD AD=BC, opposite sides of  a rectangle are congruent"which completes the proof .


Step-by-step explanation:

Given: A figure shows a rectangle ABCD having diagonals AC and DB.

Anastasia wrote the  proof  given in picture to show that diagonals of rectangle ABCD are congruent.

We can see the Statement 2 which tells that AB=CD, opposite sides of  a rectangle are congruent. In Statement 3 she used Pythagoras theorem to show AC²= BD² by using Statement 1 and 2.

Thus we can see she need to introduce two triangles named as ACD and BCD and the remaining sides to write the proof is AD=BC with correct reason i.e. opposite sides of  a rectangle are congruent.

Therefore Statement 1 would be In ΔADC and ΔBCD AD=BC, opposite sides of  a rectangle are congruent.


4 0
3 years ago
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