Use the binomial series to find the maclaurin series for the function. (use (2n)! 2nn! for 1 · 3 · 5 (2n − 1).) f(x) = 1 1 − x5
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Answer:
Because the absolute value of the test statistic is <u>less than</u> the positive critical value, there <u>is not</u> enough evidence to support the claim that there is a linear correlation between the weights of discarded paper and glass for a significance level of α = 0.05.
Step-by-step explanation:
The correlation matrix provided is:
Variables Paper Glass
Paper 1 0.1853
Glass 0.1853 1
Te hypothesis for the test is:
<em>H</em>₀: <em>ρ</em> = 0 vs. <em>H</em>₀: <em>ρ</em> ≠ 0
The test statistic is:
<em>r</em> = 0.1853 ≈ 0.185
As the alternate hypothesis does not specifies the direction of the test, the test is two tailed.
The critical value for the two-tailed test is:
The conclusion is:
Because the absolute value of the test statistic is <u>less than</u> the positive critical value, there <u>is not</u> enough evidence to support the claim that there is a linear correlation between the weights of discarded paper and glass for a significance level of α = 0.05.