All categories

3 years ago

Find the values for c and d

Mathematics

1 answer:

baherus [9]3 years ago

6 0

Answer:

c=-5

d=1

Step-by-step explanation:

$(cy^2)(4y^d)=-20y^3$

I'm going to reorder the left-hand side. Multiplication is commutative.

$(4c)(y^2y^d)=-20y^3$

Since the bases are the same in $y^2y^d$ and the operation is multiplication, I'm going to add the exponents giving me:

$4cy^{2+d}=-20y^3$

So this implies we have two equations to solve:

$4c=-20$ and $2+d=3$

So the first equation can be solved by dividing both sides by 4 giving you $c=-5$ .

The second equation can be solved by subtracting 2 on both sides giving you $d=1$ .

You might be interested in

You invest $40,000 in two funds paying 4% and 52% simple interest. The total annual interest is $2080. How much do you invest in

natali 33 [55]

9514 1404 393

Answer:

4% fund: $39,000
52% fund: $1000

Step-by-step explanation:

Let x represent the amount invested at 52%. Then (40000-x) is the amount invested at 4%. The total annual interest is ...

0.52x +0.04(40000-x) = 2080

0.48x = 480 . . . . . . . . . subtract 1600, simplify

x = 1000 . . . . . . . . . divide by 0.48

Then the amounts invested in each fund are ...

4% fund: $39,000

52% fund: $1000

6 0

2 years ago

A fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. They want to construct a 99% c

Lana71 [14]

Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.06, \sigma = 1.1$

$0.06 = 2.575*\frac{1.1}{\sqrt{n}}$

$0.06\sqrt{n} = 2.575*1.1$

$\sqrt{n} = \frac{2.575*1.1}{0.06}$

$(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}$

$n = 2228.6$

Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

7 0

3 years ago

Which of the following is a Whole Number? A: 0.252 B: 16 C:1/2 D: 14

kirza4 [7]

Answer:

The options B and D both are whole numbers

explanation:

a number without fractions; and decimals is called a whole number

hope this helps!

7 0

3 years ago

Read 2 more answers

Find the sample mean on the outputs. Does the sample mean provide some evidence that the mean of the population of all possible

soldi70 [24.7K]

I know it and it is 7

8 0

3 years ago

Write an expression that is equal to 3*2 1/4 Fourth grade Anwser

Misha Larkins [42]

6 * 1.25 because if you multiply 3 by 2 you get 6 and then you have to dib=vide 2 1/4 by 3 and you get 1.25

3 0

3 years ago