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Helga [31]
4 years ago
6

Solve the simultaneous equations. Y=5x^2 + 4x-19Y=4x+1 ​

Mathematics
1 answer:
Olegator [25]4 years ago
8 0

Answer: x1=-2

x2=2

Step-by-step explanation:

5x²+4x-19=4x+1

5x²+4x-19-4x-1=0

5x²-20=0

5x²=20

x²=20/5

x²=4

x1=-√4=-2

x2=+√4=2

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<u>Step-by-step explanation:</u>

Step 1:

To find the equality between the given terms Use the BODMAS (Brackets Orders Division Multiplication Addition Subtraction)

RHS SIDE:

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Equation after 1st modification

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Equation after Second modification

((1/8)-(15/2)+(15/4*X)+(5/8*X))

Equation after Third modification

LCM 2,4,8 is 8

And taking LCM equation changes to (1-60+30*X+5*X)/8

Equation after Final modification

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Step 2:

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By applying the BODMAS rule in the above equation we will get

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