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Svet_ta [14]
3 years ago
14

What is the justification for step 1

Mathematics
1 answer:
solniwko [45]3 years ago
6 0

Answer:

what are you talking about??????

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James and Jada together have $60. James has $9 more than twice Jada’s amount. How much money does each have?
sukhopar [10]

Answer:

$43 and

$17

Step-by-step explanation:

Let the amount James have be A and that of jada be B

Given

James and jada have $60 together

That’s

A + B = 60

And james A has $9 more than twice jada’s amount

That’s

A = 9 + 2B

We now have two equations

1. A + B = 60 and

2. A = 9 + 2B

Now put 9 + 2B as A in equation one

A + B = 60

9 +2B + B = 60

9 + 3B = 60

Subtract 9 from both sides

9 - 9 + 3B = 60 - 9

3B = 51

Divide both sides by 3

3B/3 = 51/3

B = 17

Jada has $17

Recall

A = 9 + 2B

And B = 17

Therefore

A = 9 + 2 x 17

A = 9 + 34

A = 43

James has $43

Therefore, James has $43 while jada has $17

7 0
3 years ago
Natalia has a small cubed shaped box with sides of 4 centimetres (cm), what is the volume of this box?
Alona [7]

Answer:

64cm^3

Step-by-step explanation:

5 0
2 years ago
I need help solving this equation
jok3333 [9.3K]

-5y+1y=-1+9

-4y=8

y=2

I think thats the answer

5 0
3 years ago
Read 2 more answers
What is 4x²+y²-48x+140=0 step by step please!!!!
Mekhanik [1.2K]
The answer is 4x²-48x + y²= -140

8 0
3 years ago
The height h, in feet, of objects such as thrown balls can be modeled as a function of time t, in seconds, as h(t)=−16t2+v0t+h0,
Fed [463]

Answer:

Kerry's ball stays longer in the air than Marias ball by an extra 0.582 seconds

Step-by-step explanation:

The equation that models the height, h, in feet of object thrown modeled as a time function is given as follows;

h(t) = -16t² + v₀·t + h₀

Where;

v₀ = The velocity upwards (vertical velocity)

h₀ = The initial height of the object in feet

The given parameters are;

The initial height from which Maria throws a ball = 6 feet

The initial vertical velocity with which Maria throws the ball = 40 feet per second

The initial height from which Kerry throws a ball = 5 feet

The initial vertical velocity with which Kerry throws the ball = 50 feet per second

For Maria, from the equation for the height of the object, we have;

h(t) = -16t² + v₀·t + h₀

Where for Maria, we have;

h₀ = 6 feet

v₀ = 40 ft/s

Substituting gives;

h(t) = -16 × t² + 40 × t + 6 = -16·t² + 40·t + 6

h(t) = -16·t² + 40·t + 6

The time it takes for the ball to go up and come back down again is given by the value of t, when h = 0 (ground level) as follows;

0 = -16·t² + 40·t + 6

16·t² - 40·t - 6  = 0

From the quadratic formula, we have

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

t = \dfrac{40\pm \sqrt{(-40)^{2}-4\times 16 \times (-6)}}{2\times 16} = \dfrac{40 \pm 8 \times \sqrt{31} }{32}  = \dfrac{5}{4} \pm \dfrac{\sqrt{31} }{4}

t ≈ 2.64 s or -0.14 s

Therefore, the time the ball spends in the air ≈ 2.64 s

For Kerry,  we have;

h₀ = 5 feet

v₀ = 50 ft/s

Substituting gives;

h(t) = -16 × t² + 50 × t + 5 = -16·t² + 50·t + 5

h(t) = -16·t² + 50·t + 5

Which gives;

16·t² - 50·t - 5  = 0

From the quadratic formula, we have

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

t = \dfrac{50\pm \sqrt{(-50)^{2}-4\times 16 \times (-5)}}{2\times 16} = \dfrac{50 \pm 2 \times \sqrt{705} }{32}  = \dfrac{25}{16} \pm \dfrac{\sqrt{705} }{16}

t ≈ 3.222 s or -0.097 s

he time the ball spends in the air ≈ 3.222 s

Therefore, Kerry's ball that spends approximately 3.222 seconds stays longer in the air than Maria's ball that spends approximately 2.64 seconds in the air.

The difference in the two time duration is 3.222 - 2.64 = 0.582

Kerry's ball stays longer in the air than Marias ball by an extra 0.582 seconds.

4 0
3 years ago
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