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LekaFEV [45]
3 years ago
13

An ice chest contains 3 types of drinks: 10 apple juices, 15 grape juices, and 15 bottles of water. what is the probability that

a drink selected randomly from the ice chest does not contain fruit juice?
Mathematics
1 answer:
Phantasy [73]3 years ago
4 0
15/40, or 3/8, .375,,,,,,,,,,,,
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Which set(s) of points show x in DIRECT PROPORTION to y? A) {E, C, B} only B) {G, C, A} only C) {F, E, D} and {E, C, B} only D)
polet [3.4K]

Answer:{F, G, H} and {G, C, A} only

Step-by-step explanation:

7 0
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Please help thank you!
Arte-miy333 [17]

Answer:

  • golf: $10
  • batting: $2.50

Step-by-step explanation:

We can write two equations in the two unknowns using the given relations. Let g and b represent the costs of a round of golf and a turn in the batting cage, respectively.

  5g +4b = 60 . . . . . Sylvester's expense

  3g +6b = 45 . . . . . Lin's expense

Dividing the second equation by 3 gives ...

  g +2b = 15   ⇒   2b = 15 -g

Substituting into the first equation, we have ...

  5g +2(2b) = 60

  5g +2(15 -g) = 60 . . . . . substitute for 2b

  3g = 30 . . . . . . . . . subtract 30, collect terms

  g = 10 . . . . . . . divide by 3

__

  2b = 15 -10 = 5 . . . . use the value of g to find b

  b = 2.5 . . . . . . . . divide by 2

Mini golf costs $10 per round; batting cages cost $2.50 per turn.

7 0
3 years ago
Increase 60 by 25% please
GuDViN [60]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
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Can the product of a whole number and a decimal number less than 1 ever be greater than the whole number? Give examples to suppo
masya89 [10]
No. Let's say we use 10 and 0.38. 1 X 10 is 10, so if anything is lower than 1, it will be lower than 10. Therefore, 0.38 X 10 is 3.8. This is less than the whole number, 10. Hope this is clear enough.
6 0
4 years ago
For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f
butalik [34]

\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k

Let

\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k

The curl is

\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)

where \partial_\xi denotes the partial derivative operator with respect to \xi. Recall that

\vec\imath\times\vec\jmath=\vec k

\vec\jmath\times\vec k=\vec i

\vec k\times\vec\imath=\vec\jmath

and that for any two vectors \vec a and \vec b, \vec a\times\vec b=-\vec b\times\vec a, and \vec a\times\vec a=\vec0.

The cross product reduces to

\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

\nabla\times\vec f=\vec0

which means \vec f is indeed conservative and we can find f.

Integrate both sides of

\dfrac{\partial f}{\partial y}=2xze^{2xyz}

with respect to y and

\implies f(x,y,z)=e^{2xyz}+g(x,z)

Differentiate both sides with respect to x and

\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}

2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}

4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}

\implies g(x,z)=4\sin(xz^2)+h(z)

Now

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)

and differentiating with respect to z gives

\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}

2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}

\dfrac{\mathrm dh}{\mathrm dz}=0

\implies h(z)=C

for some constant C. So

f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C

3 0
4 years ago
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