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WARRIOR [948]
3 years ago
7

Please help ASAP help please

Mathematics
1 answer:
Alja [10]3 years ago
4 0

Answer:

The ladder is 10 ft long...

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An ellipse has a vertex at (14, –1). The focus of the ellipse nearest that vertex is located at (8, –1). If the center of the el
zavuch27 [327]
Refer to the diagram shown below.

The right vertex is at (14, -1), and the center is at (-1, -1).
Therefore the semi-major axis is
a = 14 - (-1) = 15

The right focus is at (8, -1).
Therefore
c = 8 - (-1) = 9.

The distance of the directrix from the center is
d = c²/a = 9²/15 = 81/15 = 27/5.

Therefore the equation for the left directrix is
x = -1 - 27/5 = -32/5

Answer: x = -27/5

6 0
4 years ago
Read 2 more answers
The circle below has a center D and its diameter is 10 feet. Given that m angle A D B equals 35 degree, find the length of major
goldfiish [28.3K]

The length of major arc ACB with angle measure of 325° and diameter of 10 feet is (325/36)π

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

angle of arc ACB = 360° - 35° = 325°

The length of major arc ACB = (325/360) * π * 10 = (325/36)π

The length of major arc ACB with angle measure of 325° and diameter of 10 feet is (325/36)π

Find out more on equation at: brainly.com/question/2972832

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8 0
2 years ago
What is the hcm of 18 and 45
Rus_ich [418]

Answer:

90

Step-by-step explanation:

90 Or, we can say that it is a method of breaking down the given integer into its prime factors. Therefore, the HCF of 18 and 45 is 9. Therefore, the HCF of 18 and 45 is 90.

6 0
3 years ago
Brainiest to who ever answers first
earnstyle [38]

Answer:

18/24 for the first one

Step-by-step explanation:

5 0
3 years ago
A circle has a diameter of 12 units, and its center lies on the x-axis. What could be the equation of the circle?
ycow [4]

Answer:

x^{2} +y^{2} =36

Step-by-step explanation:

A circle centered at (0,0) with radius r is x^{2} +y^{2} =r^{2}

Since your circle has diameter of 12, then its radius is 6.  Then r^{2} =36

So a possible answer is:  x^{2} +y^{2} =36

If you want to move the location of the center, but keep it on the x-axis, then add or subtract a number to the x, such as this:

(x+4)^{2} +y^{2} =36

The center of this circle would be (-4, 0) which is still on the x-axis.

8 0
3 years ago
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