![\bf \begin{array}{lllll} round(x)&\boxed{1}&2&3&\boxed{4}\\\\ wrestlers[f(x)]&\boxed{64}&32&18&\boxed{9} \end{array} \\\\\\ slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby \begin{array}{llll} average\ rate\\ of\ change \end{array}\\\\ -------------------------------\\\\ f(x)= \qquad \begin{cases} x_1=1\\ x_2=4 \end{cases}\implies \cfrac{f(4)-f(1)}{4-1}\implies \cfrac{9-64}{4-1}\implies \cfrac{-55}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blllll%7D%0Around%28x%29%26%5Cboxed%7B1%7D%262%263%26%5Cboxed%7B4%7D%5C%5C%5C%5C%0Awrestlers%5Bf%28x%29%5D%26%5Cboxed%7B64%7D%2632%2618%26%5Cboxed%7B9%7D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0Aslope%20%3D%20%7B%7B%20m%7D%7D%3D%20%5Ccfrac%7Brise%7D%7Brun%7D%20%5Cimplies%20%0A%5Ccfrac%7B%7B%7B%20f%28x_2%29%7D%7D-%7B%7B%20f%28x_1%29%7D%7D%7D%7B%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%7D%5Cimpliedby%20%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Aaverage%5C%20rate%5C%5C%0Aof%5C%20change%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0Af%28x%29%3D%20%20%20%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ax_1%3D1%5C%5C%0Ax_2%3D4%0A%5Cend%7Bcases%7D%5Cimplies%20%5Ccfrac%7Bf%284%29-f%281%29%7D%7B4-1%7D%5Cimplies%20%5Ccfrac%7B9-64%7D%7B4-1%7D%5Cimplies%20%5Ccfrac%7B-55%7D%7B3%7D)
55 over 3, or 55 wrestlers for every 3 rounds, but the wrestlers value is negative, thus 55 "less" wrestlers for every 3 rounds on average.
The answer is 0.91 because it is
Answer:
1.75liters per bottle
Step-by-step explanation:

first let's name a couples of variable
• the number of adults tickets sold: a
• the number of children tickets sold: c
From the problem we know
a + c = 128
and
$5.40c + $9.20a = $976.20
1) solve the equation to alpha
a+c-c = 128 -c
a+0=128-c
a=128-c
2) substitute (128 - c) for a in the second equation and solve to c
$5.40c + $9.20a = $976.20 become
$5.40c + $9.20(128 - c) = $976.20
$5.40c + ($9.20 × 128) - ($9.20 - c) = $976.20
$5.40c - $9.20c + $ 1177.6 = $976.20
($5.40 - $9.20)c +$1177.6 = $976.20
-$3.80c + $1177.6 = $9.76.20
-$3.80c + $1177.60 - $1177.60 = $976.20 - $1177.60
-$8.30c + 0 = $201.40
-$3.80c = - $201.40
-$3.80c. -$201.40
________. = _________
-$3.80. -$3.80
-$3.80c. -$201.40
________. = _________. - they are 4 cut the no
-$3.80. -$3.80
c = $201.40
________
3.80
c = 53
Answer:
The standard form of this equation is -8x + 3y = -68
Step-by-step explanation:
In order to find this, first solve for the constant.
y = 8/3x - 68/3
-8/3x + y = -68/3
Now we multiply by 3 to get them all equal to integers.
-8x + 3y = -68