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Anni [7]
3 years ago
8

A normal female X H X H marries a man who has hemophilia.

Biology
1 answer:
Citrus2011 [14]3 years ago
6 0

Answer:

0%

Explanation:

Normal female genotype = X^HX^H

Genotype of a man with hemophilia = X^hY

Crossing the two in marriage:

X^HX^H   x   X^hY

Progeny: X^HX^h, X^HY, X^HX^h, and X^HY

<em>The two sons from the cross have the genotype </em>X^HY<em> and are therefore free from hemophilia.</em>

Hence, the percentage of their sons that will have hemophilia is zero (0).

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