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Reika [66]
2 years ago
7

A scientist investigated DNA replication in two groups of cells, labeled A and B. She injected radioactively labeled nucleotides

into cells of each group and allowed DNA replication to begin. When replication was halfway completed, she injected a drug into the cells to stop replication. She then examined the cells to determine the distribution of the newly-synthesized DNA. She found each cell of group A had many segments of new DNA in its nucleus, while each cell of group B had a single segment of new DNA in its cytoplasm. What can the researcher conclude about the cells?
Biology
1 answer:
hichkok12 [17]2 years ago
3 0

Answer:

A is a eukaryotic cell while B is a prokaryotic cell

Explanation:

The researcher can conclude that <u>cell A is eukaryotic while cell B is prokaryotic.</u>

In eukaryotic cells, the <u>DNA is located majorly in the nucleus and the replication of the DNA happens in the nucleus</u>. Hence, it is only logical to find segments of new DNA in the nucleus of cell A during replication.

<u>Prokaryotic cells, however, lack a nucleus</u>. Their DNAs lie freely within the cytoplasm. This thus means that replication can only happen in the cytoplasm. Hence, it follows logically to find a new DNA segment in the cytoplasm of cell B.

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<u>Answer:</u>

Discovery of vaccine for smallpox, viruses and actual organisms that cause many diseases lead to the development of Germ Theory.

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How is carbon transferred from the biosphere to the hydrosphere?
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Explanation:

Hope this helps.

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Why do calculated recombination frequencies between pairs of loci that are located far apart underestimate the true genetic dist
den301095 [7]

Answer:

B. As the distance between loci increases, some multiple crossovers go undetected such that the relationship between recombination frequency and map distance ceases to be linear.  

Explanation:

When calculating recombination frequencies, and hence, map distances, we might notice that these distances are not completely additive. They might vary. <em>For example, let us say that we have three genes, A, B, and C, in that order. </em>We calculated that the <em>distance between A and B equals 5.9</em> MU and that <em>B and C are 19.5 MU apart.</em> According to this, we might say that the <em>total distance between A and C is 25.4 MU (5.9 + 19.5). </em>However, after a<em> two-point calculation between A and C, the value equals 23.7 MU. </em>

The recombination frequency between these two genes located in the extremes and far apart underestimate the actual genetic distances between them because there might occur other crossing-overs that were not detected. This is <em>when calculating the distance between A and C, we probably will not detect the occurrence of a double recombinant between them, and hence, we might sub-estimate the real distance.</em>

The relationship between the actual map distance (number of crossing overs) and the recombination frequency between two loci, is not lineal. The farther apart are the two genes, the worse is the distance estimation.  

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