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-BARSIC- [3]
4 years ago
13

Use the linear combination method to solve the system of equations. 2x-3y=13 and x+2y=-4

Mathematics
1 answer:
Nesterboy [21]4 years ago
5 0
2x - 3y = 13  /*2
x + 2y = - 4   /*(3)

4x - 6y = 26
3x + 6y = - 12
---------------------- + 
4x + 3x = 26 - 12
7x = 14
x = 2

y = ( - 4 - x)/2 = ( - 4 - 2)/2 = - 6/2 = - 3

Answer 
( 2; - 3)
 

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7(8x - 6y + 9) = i need help on this one
snow_tiger [21]

Answer:

56x-42x+63

Step-by-step explanation:

8 0
3 years ago
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The equations 9 x minus 10 y = 6, 8 x minus 10 y = negative 23, 9 x + 10 y = negative 16, and 8 x + 10 y = 13 are shown on the g
neonofarm [45]

Answer:

Step-by-step explanation:

The two equations are 8x-10y=-23 and 9x+10y=-16.

If you plug them both into a graphing calculator, you will see that the point where they cross (the solution) is (-2.3, 0.5).

The answer is A.

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3 years ago
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HELP!!!!
ss7ja [257]
<h3>3 Answers: Choice D, Choice E, Choice F</h3>

============================================================

Explanation:

The inequality 6x - 10y ≥ 9 solves to y ≤ (3/5)x - 9/10 when you isolate y.

Graph the line y = (3/5)x - 9/10 and make this a solid line. The boundary line is solid due to the "or equal to" as part of the inequality sign. We shade below the boundary line because of the "less than" after we isolated for y.

Now graph all of the points given as I've done so in the diagram below. The points in the blue shaded region, or on the boundary line, are part of the solution set. Those points are D, E and F.

We can verify this algebraically. For instance, if we weren't sure point E was  a solution or not, we would plug the coordinates into the inequality to get...

6x - 10y ≥ 9

6(5) - 10(2) ≥ 9 .... plug in (x,y) = (5,2)

30 - 20 ≥ 9

10 ≥ 9 ... this is a true statement

Since we end up with a true statement, this verifies point E is one of the solutions. I'll let you check points D and F.

-----------

I'll show an example of something that doesn't work. Let's pick on point A.

We'll plug in (x,y) = (-1,1)

6x - 10y ≥ 9

6(-1) - 10(1) ≥ 9

-6 - 10 ≥ 9

-16 ≥ 9

The last inequality is false because -16 is smaller than 9. So this shows point A is not a solution. Choices B and C are non-solutions for similar reasons.

3 0
3 years ago
Please help ASAP
REY [17]
<h3><u>Answer :</u><u>-</u><u> </u></h3>

<u>\frac{1}{2}</u>

<h3><u>Question :- </u></h3>

find \:  \frac{ - 4}{5}  \times  \frac{3}{7}  \times  \frac{15}{16} \times ( \frac{ - 14}{9} )

<h2><u>Solution :- </u></h2>

<h3><u>First </u><u>way:</u></h3>

<h3>• we have ; </h3>

\frac{ - 4}{5}  \times  \frac{3}{7}  \times  \frac{15}{16}  \times ( \frac{ - 14}{9} )

<h3>So then , </h3>

=  >  \: ( -  \frac {4 \times 3}{5 \times 7} ) \times ( \frac{15 \times ( - 14)}{16 \times 9}

=  >  \:  \frac{ - 12}{35}   \times ( \frac{ - 35}{24} ) =  \frac{ - 12 \times ( - 35)}{35 \times 24}  =  \frac{1}{2}

<h3><u>Second way : </u></h3>

\frac{ - 4}{5}  \times  \frac{3}{7}  \times  \frac{15}{16}  \times  (\frac{ - 14}{9} )

=  >  \: ( \frac{ - 4}{5}  \times  \frac{15}{16} ) \times  \binom{3}{7}  \times ( \frac{ - 14}{9} )

[ ↑ Using commutativity and Associativity ] ...

\frac{ - 3}{4}  \times ( \frac{ - 2}{3} ) =  \frac{1}{2}

7 0
3 years ago
Josh decided to rent an SUV for a family trip he was planning. On the way
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Answer: a collision damage waiver

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