Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
Step-by-step explanation:
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It would be $7.50 because 4 ounces equals $1 so 30/4 =7.5
U have to solve it then right the equation down