1. Convert the mixed numbers into improper numbers (-3 2/5 = -17/5 and 8 1/5 = 41/5). Then add 17/5 to both sides when means b=58/5
2. Multiply both sides by the reciprocal of -7/3 (which is -3/7). So n=18
Answer:
C is the answer i
Step-by-step explanation:
By applying the theorem of intersecting secants, the measure of angle XYZ is equal to: A. 35°.
<h3>How to determine angle <XYZ?</h3>
By critically observing the geometric shapes shown in the image attached below, we can deduce that they obey the theorem of intersecting secants.
<h3>What is the theorem of
intersecting secants?</h3>
The theorem of intersecting secants states that when two (2) lines intersect outside a circle, the measure of the angle formed by these lines is equal to one-half (½) of the difference of the two (2) arcs it intercepts.
By applying the theorem of intersecting secants, angle XYZ will be given by this formula:
<XYZ = ½ × (m<WZ - m<XZ)
Substituting the given parameters into the formula, we have;
<XYZ = ½ × (175 - 105)
<XYZ = ½ × 70
<XYZ = 35°.
By applying the theorem of intersecting secants, we can infer and logically deduce that the measure of angle XYZ is equal to 35°.
Read more on intersecting secants here: brainly.com/question/1626547
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Answer:
x = 10
Step-by-step explanation:
The total measures of a circle must add up to 360°. In the diagram given there are two angles that are not given, however, both of these should be equal to each other. That means that the sum of the other two angles ('5x - 5' and 93°) must be equal to the other angle of the same measure (138°):
5x - 5 + 93 = 138
Combine like terms: 5x + 88 = 138
Subtract 88 from both sides: 5x + 88 - 88 = 138 - 88 or 5x = 50
Divide by 5: 5x/5 = 50/5 or x = 10
A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
