The p-value from the hypothesis test is 0.142 i.e., greater than the given significance level of 0.05. So, the null hypothesis is not rejected. The z-score for the given sample is 1.471.
<h3>What is the decision rule for the p-value approach to hypothesis testing?</h3>The decision rule based on p-value states,
- If p > α (significance level), then the null hypothesis is not rejected
- If p < α (significance level), then the null hypothesis is rejected in favor of the alternative hypothesis.
Since it is given that the valve would produce a mean pressure of 5.4 pounds/square inch. I.e., μ = 5.4 p/si
So, Defining the hypothesis:
Null hypothesis H0: μ = 5.4
Alternative hypothesis Ha: μ ≠ 5.4
It is given that,
The valve was tested on 24 engines. I.e., Sample size n = 24
The sample mean X = 5.7
Standard deviation σ = 1.0 and
The significance level = 0.05
Since the population distribution is approximately normal,
the test statistic is calculated as follows:
z = (X - μ)/(σ/)
On substituting the value,
z = (5.7 - 5.4)/(1.0/)
= (0.3)/0.204
= 1.471
Fron this z-score, the p-value is calculated as 0.142.
Since, the value of p > 0.05 (significance level), the null hypothesis is not rejected.
Learn more about hypothesis testing here:
#SPJ4