<span>y=−3x+2</span> is a linear equation in slope-intercept form with
slope <span>m=<span>(−3)</span></span>
(and y-intercept <span>=2</span>)
We want the equation of a line with slope <span>m=<span>(−3)</span></span> through the point <span>(<span>−2</span>,<span>−8</span>)</span>
Using the point-slope linear equation form:
<span><span>(y−<span>(−8)</span>)</span>=<span>(−3)</span><span>(x−<span>(−2)</span>)</span></span>
Simplifying
<span>y+8=−3x−6</span>
or, in standard form
<span>3x+y=−<span>14</span></span>
Answer:
BC = 22
Step-by-step explanation:
BD = 67
Bc = 3x - 2
CD = 4x + 13
BC + CD = BD (Given)
3x - 2 + 4x + 13 = 67
3x + 4x -2 + 13 = 67
7x + 11 = 67
7x = 67 - 11
7x = 56
x = 56 ÷ 7
x = 8
now instead of x put 8
Bc = 3x - 2
BC = 3(8) -2
BC = 24 -2
BC = 22
