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Dennis_Churaev [7]
4 years ago
10

Richard earns $25 allowance each week how can she mentally compute her total earnings after seven weeks

Mathematics
1 answer:
MaRussiya [10]4 years ago
3 0

she would have to multiply 25 × 7 to get $175

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A diagonal shortcut across a rectangular lot is 130 feet long. The lot is 50 feet long. What is the other dimension of the lot
ryzh [129]
We use the pithagorean formula: x^2 = 130^2 - 50^2 = 16900 -2500 = 14400;
then, x = \sqrt{14400} = 120 feet has the other dimension of the lot.
6 0
3 years ago
Emma packed gift bags to give to the
Alex17521 [72]

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Graph the system of equations on graph paper. {8x+6y=482x−3y=−6 Which statements are true about the solution to the system of eq
GuDViN [60]

Answer:

The answers are that the x-coordinate is 3, the y-coordinate is 4 and it is in quadrant I

Step-by-step explanation:

To find these answers, start by solving the system. We can do this by multiplying the second equation by 2 and adding them together.

8x + 6y = 48

4x - 6y = -12

-------------------

12x = 36

x = 3

Next, find the y value by plugging in the x value to either equation and solving.

2x - 3y = -6

2(3) - 3y = -6

6 - 3y = -6

-3y = -12

y = 4

6 0
3 years ago
A box-contains 3 blue and 2 red marbles while another box contains 2
Illusion [34]

Answer:

3/5

Step-by-step explanation:

(3/5) · (1/2) over (3/5) · (1/2) + (2/5) · (1/2)

= 3/5

3 0
4 years ago
Which second-degree polynomial function f(x) has a lead coefficient of 4 and roots 5 and 2? f(x) = 4x² +7x+10 f(x)=4x²+28x+40 O
makkiz [27]

The second-degree polynomial function f(x) that has a lead coefficient of 4 and roots 5 and 2 is f(x) = 4x² -28x + 40. The correct option is the last option f(x)=4x²-28x+40​

<h3>Quadratic equation</h3>

From the question, we are to determine which second-degree polynomial function f(x) has a lead coefficient of 4 and roots 5 and 2

To determine this, we will use the given roots to determine the equation

The roots are 5 and 2

Thus

x = 5 and x = 2

x - 5 = 0 and x - 2 = 0

Therefore,

(x -5)(x -2) = 0

Distributing

x(x -2) -5(x -2)  = 0

x² -2x -5x + 10 = 0

x² -7x + 10 = 0

Now, multiplying through by 4, we get

4x² -28x + 40 = 0

Thus, the function becomes f(x) = 4x² -28x + 40

Hence, the second-degree polynomial function f(x) that has a lead coefficient of 4 and roots 5 and 2 is f(x) = 4x² -28x + 40. The correct option is the last option f(x)=4x²-28x+40​

Learn more on Quadratic Equation here: brainly.com/question/19257086

#SPJ1

8 0
2 years ago
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