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Mandarinka [93]
3 years ago
9

Which of the following is equal to the rational expression when x does not equal -2 or -6?

Mathematics
1 answer:
MissTica3 years ago
6 0

Answer:

B. 3 / (x+6)

Step-by-step explanation:

3(x+2)/(x+6)(x+2) = 3 / (x+6)

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Convert 30 m/s to miles per hour.<br> Use 1 mile per hour = 1.61 km/h
ss7ja [257]

Answer:

1 = 1.61

30 = x

1.61 x 30 =

48.3

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3 years ago
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What equation could you use to solve the problem below? The math clubs car can travel 9 m in a second. The race track for the so
WARRIOR [948]

Answer:

D

Step-by-step explanation:

Because if you divide it becomes 3

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2 years ago
Find the exact value of each expression . Do not use a calculator .
Alex73 [517]
The attached table is one that it is convenient for you to memorize as long as you're taking courses involving angles. For the inverse functions, find the column corresponding to the function, then look for the value in that column. The angle at the beginning of that row is the answer to your question.

8. \cos^{-1}(0)= 90^{\circ}=\dfrac{\pi}{2}

9. \sin^{-1}(1)= 90^{\circ}=\dfrac{\pi}{2}

10. \tan^{-1}\left( \dfrac{\sqrt{3}}{3} \right)=30^{\circ}=\dfrac{\pi}{6}

8 0
3 years ago
11 people enter a pie eating contest. how many ways can the prize be awarded to the top 3
True [87]
This is a permutation question because we care about the order.
We can demonstrate this by letting each person be a person in the pie eating contest.

A   B   C   D   E   F   G   H   I   J   K

_   _   _

Now, there are 11 ways for the first prize to be won, since there are no restrictions upheld. Let's say A wins the first prize.

B   C   D   E   F   G   H   I   J   K

A   _   _

Now, assuming prizes aren't shared, there are only ten people left to win the second prize.
Using this logic, then we can say that nine can win the third prize.

Thus, our answer is 11 · 10 · 9 = 990 ways.

However, this method works for this question.
What happens when the number of places we want gets significantly larger?
That's when we introduce the permutation formula.

We know that 11·10·9·8·7·6·5·4·3·2·1 = 11!, but we don't want 8! of them.
This is the formula for permutation.

^{11}P_3 = \frac{11!}{(11 - 3)!} = 990
8 0
3 years ago
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