3 years ago

Which of the following is equal to the rational expression when x does not equal -2 or -6?

Mathematics

1 answer:

MissTica3 years ago

6 0

Answer:

B. 3 / (x+6)

Step-by-step explanation:

3(x+2)/(x+6)(x+2) = 3 / (x+6)

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Please answer this question, will give brainliest!

Ad libitum [116K]

Answer:

I dont really know the answer.. but ill try; if its wrong I am so sorry;

Step-by-step explanation:

First you must get the area of a circle, which is; A= pi r squared

and all you have to do is fill it in like this;

A= 3.14 x 2.0

A= 6.28

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3 years ago

How do i solve this (15 points)

GaryK [48]

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3 years ago

What is the mean absolute deviation (MAD) of the data set?

erastova [34]

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3 years ago

2+2*3+2*2+4=what is the correct answer?<br> a 12<br> b14<br> c16<br> d32

GaryK [48]

Answer: C

Step-by-step explanation:

2×3=6, 2×2=4, so that leaves you with 2+6+4+4 which adds up to 16

5 0

3 years ago

Read 2 more answers

Explain why S = {(5, 4, -2), (-15, -12, 6), (10, 8, -4)} is NOT a basis for R^3 (1 point Sis linearly dependent and spans R3 S i

earnstyle [38]

$S$ would be a basis for $\mathbb R^3$ if

(1) the vectors in $S$ are independent, and

(2) the vectors span $\mathbb R^3$ .

Linear independence requires that $c_1=c_2=c_3=0$ is the only solution to

$c_1(5,4,-2)+c_2(-15,-12,6)+c_3(10,8,-4)=(0,0,0)$

These vectors are not linearly independent because if $c_1=3$ , $c_2=1$ , and $c_3=0$ , we have

$3(5,4,-2)+(-15,-12,6)=(15-15,12-12,-6+6)=(0,0,0)$

so $S$ is not a basis for $\mathbb R^3$ .

7 0

3 years ago