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prohojiy [21]
3 years ago
13

In AHIJ, m_H=(8x-6)°, m_1=(2x-4)', and m2)=(x-8)". Find mcH.

Mathematics
1 answer:
blondinia [14]3 years ago
5 0

9514 1404 393

Answer:

  m∠H = 138°

Step-by-step explanation:

Perhaps you have ΔHIJ and want the measure of ∠H.

  ∠H +∠I +∠J = 180°

  (8x-6) +(2x-4) +(x-8) = 180

  11x -18 = 180 . . . . . . collect terms

  11x = 198 . . . . . . . . . add 18

  x = 18 . . . . . . . . . . .  divide by 11

Then angle H is ...

  m∠H = (8(18) -6)°

  m∠H = 138°

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<span>The graph is attached.

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We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
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For the second equation,
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y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.

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Plot these points for both equations and connect them to draw the line.</span></span>

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