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Mnenie [13.5K]
3 years ago
9

Multiple Choice

Computers and Technology
1 answer:
earnstyle [38]3 years ago
7 0
1 )  B ) I<span>ntersections.
2 ) A ) Freeways ( i believe )
Matchmaking
-</span><span>Retractable STOP sign arm ( school bus ) 
-Jaywalking ( d</span><span>angerous pedestrian practice ) 
- Moped ( </span><span>cross between bicycle and motorcyble ) 
1 ) I would say the </span><span>major cause of collisions between cars and motorcycles is due to motorcycles driving into lane/places cars can not get into. - lane splitting, traffic jam - 
2 )When there is a yeild sign or a crossing sign, it's </span><span>legal for a pedestrian to cross a roadway. ( I believe )
3)</span><span> Motorists must keep a constant lookout for pedestrians crossing and at intersections. 
4) I know when trucks are driving up or anything similar they get faster and sometimes cant control, so there are certian stops that trucks go up to make them slow down. I honeslty don't know if you should go around or not. But i hope this helps.
</span>
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What does clicking and dragging the fill handle in excel
Olegator [25]

Answer:

The fill handle copies the same values, formulas, or fills a series of dates, texts, numbers, and other data to a desired number of cells. ... Click and hold the handle, then you can drag up, down, across over other cells. When you release your mouse button, it auto-fills the content to the cells you dragged over.

5 0
2 years ago
Write code which takes a user input of a String and an integer. The code should print each letter of the String the number of ti
Alexus [3.1K]

import java.util.Scanner;

public class JavaApplication70 {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.println("Input a String:");

       String txt = scan.nextLine();

       System.out.println("Input an integer:");

       int num = scan.nextInt();

       String newTxt = "";

       int w = 0;

       for (int i = txt.length()-1; i >= 0; i--){

           char c = txt.charAt(i);

           while (w < num){

               newTxt += c;

               w++;

           }

           w = 0;

       }

       System.out.println(newTxt);

   }

   

}

I hope this helps!

7 0
3 years ago
Read 2 more answers
How does a light bulb work
koban [17]
A light bulb is usually powered by a wire producing electricity. The energy can also come from wind turbines or solar panels.

Hope this helps
7 0
4 years ago
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What are some of the strategies that you use for confronting a complex problem and breaking it down into smaller pieces? How mig
bazaltina [42]

Answer:

Breaking it down I guess for me, you could take down all the possible things that you could do. Eliminating things, one by one. It could help working on a computer by not letting yourself get over-whelmed by all your programming and thinking "alright, this THEN this."

Explanation:

8 0
3 years ago
This program is to compute and write to a file the GPA for student scores read from an input file. The point values of the grade
VARVARA [1.3K]

Answer:

#Take input from the user

filename=input('Enter name of input file: ')

total_units=0#Total number of units for a student

total_score=0#Total score of a student

#Assign a score to each grade. I have reduced 0.33 for each grade. Change here if you need to

grade={'A':4.0,'A-':3.67,'B+':3.34,'B':3.01,'B-':2.68,'C+':2.35,'C':2.02,'C-':1.69,'D+':1.36,'D':1.03}

try:

with open(filename,"r") as input_file:#Open the file for input(reading)

output_file=open("GPA_output.txt","w") #Create and open GPA_output.txt if it doesn't exist for writing

for student_record in input_file:#read from input file

if("," in student_record):#if there is a , that means this is the student name

student_name=student_record.strip('\n')#Remove \n from student name

continue

else:

if(" " in student_record):#If a line contains spaces then its the student's grades for a course

student=student_record.split(" ")#Split to find the coursename, units and grade

#student[0]=coursename student[1]=units student[2]=grade

total_units+=int(student[1])#Calculate total units for 1 student

total_score+=int(student[1])*grade[student[2].strip('\n')]#Find the total score of a student

#grade[student[2]] will lookup for the score that we initialized earlier

#if student has a grade as A then this will look up as grade['A'] which will return 4

#Find the total score as product of this grade and units for this course

continue

else:

if(total_units>0):#Check if score has been calculated for a student earlier

print("in")

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

if(total_units>0):#Essential for the case when the file doesn't end with a new line(Check if total_units is not 0) which means a record is pending

#to be written to the file

GPA=total_score/total_units#Calculate the GPA

output_file.write("%-26s%.2f\n" % (student_name, GPA))#Write the GPA and Student Name in the required format

total_units=0#reset the units

total_score=0#reset the score

input_file.close()#Close the input file

output_file.close()#Close the output file

except IOError as e:

print("Problem in Opening the required file")#Print a message if file cannot be opened

Explanation:

The program has been tested for all 3 scenarios mentioned i.e.

a. If the file ends without \n

b. If the file ends with 2 \n

c. If the file ends with 1 \n

PS: The Program will run irrespective of how it ends. Even if there are many \n at the end of file, the program will be fine.

3 0
3 years ago
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