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3 years ago

Solve. 3a+a=? and explain

Mathematics

2 answers:

Tresset [83]3 years ago

8 0

You can't answer that, because 3 can't be added with a. It could be 3₃ + 19. Who knows!

777dan777 [17]3 years ago

3 0

4a

If it helps, there is actually a 1 before the a. So, the problem reads 3a + 1a. now you just add the 3 and 1 and attach the variable.

Hope this helps

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What are the zeros of the polynomial function F(x) = xᶺ2 – 5x – 6?

zavuch27 [327]

First, you need to factor the function. You can do this by finding a pair of numbers whose product is equal to the c term (-6) and whose sum is equal to the b term (-5). These numbers are -6 and 1 (-6*1=-6, -6+1=5). The factored expression takes the form:

(x+1)(x-6)=0

The zeroes can be found by flipping the signs in the parentheses. The zeroes are equal to each number.

The zeroes are -1 and 6.

Hope this helps!!

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3 years ago

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Find the intersection of the three sets: A = {–9, 0, 5}, B = {0, 2, 5, 8}, C = {–9, 2, 5}.

kkurt [141]

Answer:

the intersections of these sets is 5

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3 years ago

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4. Mia ran 10 laps in 8 minutes. Shawna ran 4 laps in 3 minutes. Which person ran at a faster rate? * O Mia ran at a faster rate

aksik [14]

Answer:

Shawna ran at a faster rate.

Step-by-step explanation:

Because of Shawna ran for 10 minutes just like Mia, it would take her 7.5 mins while Mia took 8minutes to run 10 laps

4 0

3 years ago

The original line has the equation of y=-2x+8

enot [183]

The new equation of line that is perpendicular to the original that goes through the point (6, -1) in slope intercept form is $y = \frac{1}{2}x - 4$

<h3>Solution:</h3>

Given that original line has the equation of y = -2x + 8

We have to write a new equation that is perpendicular to the original that goes through the point (6, -1)

Let us first find slope of original line

The slope intercept form of line is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form and given original equation, we get "m = -2"

Thus slope of original line "m" = -2

We know that product of slope of a line and slope of line perpendicular to it are always -1

slope of original line x slope of line perpendicular to it = -1

$\begin{array}{l}{-2 \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{1}{2}}\end{array}$

Let us find equation of line with slope m = 1/2 and passes through point (6, - 1)

Substitute $m = \frac{1}{2}$ and (x, y) = (6, -1) in eqn 1

$-1 = \frac{1}{2} \times 6 + c\\\\-1 = 3 + c\\\\c = -4$

Thus the required equation of line is:

Substitute "c" = -4 and $m = \frac{1}{2}$ in eqn 1

$y = \frac{1}{2}x - 4$

Thus the equation of line perpendicular to original line is found

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3 years ago

What are the amplitude period phase shift and midline for F(x)=-4cos(3x-3.14)+2

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

f(x) = -4cos(3x-pi) +2

compare to f(x) = A cos (B(x+C))+D

A is amplitude =4

Period is 2pi/B so period = 2pi/3

Phase shift is C so phase shift = -pi (this could be positive if it shifted to the left)

Midline is at D so midline is y=2

4 0

3 years ago