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Nadya [2.5K]
3 years ago
7

A rectangular pool is 18 meters wide and 24 meters long. If you swim diagonally across the pool, how many meters would you be sw

imming?
Mathematics
1 answer:
Zanzabum3 years ago
6 0
Using the Pythagorean theorem, the diagonal measure is found as
  √((18 m)² +(24 m)²) = √(324 +576) m = √900 m
  = 30 m

You would be swimming 30 meters.
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Which expression has the same value as 7÷9 over 10
Maurinko [17]
This may be wrong but I'm going to go with B. 1/7 x 9/10



Hope this helps! ( Probably didn't help in any way but I tried).
5 0
3 years ago
1 2 TIME REMAIN 50:24 How could Theo check his work? Check all that apply. Theo solved n + 5 = 11 for the unknown. The steps he
elena-14-01-66 [18.8K]

Answer:

so first you do the work than check

Step-by-step explanation:

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Using Heron’s formula, calculate the area of the parallelogram to the nearest tenth of a square unit.
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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
A supermarket finds that the number of boxes of a new cereal sold increases each week. in the first week, only 16 boxes of the c
vaieri [72.5K]
For this case, the arithmetic sequence is given by:
 an = 17n-1
 Let's check it:
 First week:
 n = 1:
 a1 = 17 (1) -1
 a1 = 17-1
 a1 = 16
 Second week:
 n = 2:
 a2 = 17 (2) -1
 a2 = 34-1
 a2 = 33
 Third week:
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 a3 = 17 (3) -1
 a3 = 51-1
 a3 = 50
 Answer:
 
the explicit rule for the arithmetic sequence that defines the number of boxes of cereal sold in week n is:
 
an = 17n-1
6 0
3 years ago
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