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makkiz [27]
3 years ago
15

Solve for x.....................

Mathematics
2 answers:
Aliun [14]3 years ago
8 0

Answer:

15

Step-by-step explanation:

In order to find the the value of x, first we need to calculate the length of the perpendicular dropped from the right angle to the hypotenuse of the given triangle.

Therefore, by geometric mean property, we have:

l(perpendicular)  \\ =  \sqrt{9 \times (25 - 9)}  \\ =  \sqrt{9 \times 16}  \\ =  \sqrt{144}  \\  l(perpendicular) = 12 \: units \\  \\ Now \: by \: Pythagoras \: Theorem:\\  {x}^{2}  =  {9}^{2}  +  {12}^{2}  \\  {x}^{2}  = 81 + 144 \\  {x}^{2}  = 225 \\ x =  \sqrt{225}  \\ x = 15

solniwko [45]3 years ago
7 0
The answer that’s you are looking for for this problem is 15
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Can a triangle be formed with 4cm 8cm and 12cm
worty [1.4K]
No. 4^2 + 8^2 or 16 + 64 is 80, and the hypotenuse, 12 (144) is not 80.
7 0
3 years ago
Multiple Choice
Zanzabum

A) Answer: A. 22.5 cm, 30 cm, and 37.5 cm


Setting the unity measurement as x, the three sides will be 3·x, 4·x, and 5·x. The sum of the three sides will be (3 + 4 + 5)·x = 12·x; this corresponds to the perimeter, therefore:

12·x = 90 cm


We can solve for x:

x = 90 / 12 = 7.5 cm


Hence, the sides will be:

7.5 · 3 = 22.5 cm

7.5 · 4 = 30 cm

7.5 · 5 = 37.5 cm


This situation is represented in option A (which is also the only option whose sides add up to 90).



B) Answer: C. never true


We have:

6 + 8x - 9 = 11x + 14 - 3x


Bring all the terms with x on the left, by subtracting from both sides 11x and -3x, and all the numbers on the right by subtrcting from both sides 6 and -9:

6 + 8x - 9 - 11x - (-3x) - 6 - (-9) = 11x + 14 - 3x - 11x - (-3x) - 6 - (-9)


Cancel out the opposite terms from each side:

8x - 11x + 3x = 14 - 6 + 9


Combine likely terms:

0x = 17


Now you should ask yourself: what number multiplied by zero gives 17 as a result? The answer is none because a number multiplied by zero always equals zero.


Hence, the statement is never true.


C) Answer: r \leq \frac{1}{5}


We have:

5r + 4 ≤ 5


Subtract 4 from both sides:

5r + 4 - 4 ≤ 5 - 4


Combine likely terms:

5r ≤ 1


Divide both sides by 5:

\frac{5r}{5} \leq \frac{1}{5}

r \leq \frac{1}{5}


To graph the set of solutions, you need to set:

y₁ = 5x + 4 and

y₂ = +5


Plot these two lines:

y₂ is a horizontal line at a height of 5;

y₁ is a line passing through (0, 4) and (1, 9)


The set of solutions will be the part of the graph in which y₁ lies underneath y₂ (see picture attached), that happens for x \leq \frac{1}{5}.





4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%5C%5C%5Cfrac%7B9%2B%5Csqrt%7B17%7D%20%7D%7B2%7D" id="TexFormula1" title="\sqrt{\\\f
Alborosie

\huge\underline\pink{✏ANSWER}

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4 0
3 years ago
PLZ HELP! A train averages a speed of 90 miles per hour across the plains and 37.5 miles per hour through the mountains. If a tr
Kruka [31]

Answer:

3.8

Step-by-step explanation:

A train averages a speed of 90 miles per hour across the plains and 37.5 miles per hour through the mountains.

If a trip of 300 miles took 3 hour and 48 minutes, how much of it was through the mountains?

Let d = distance traveled at 37.5 (thru the mountains)

then

(300-d) = distance traveled at 90 mph

Write a time equation, time = dist/speed

change 3 hr 48 min to hrs: 3 + 48/60 = 3.8 hrs

plain time + mountain time = 3.8 hrs

%28300-d%29%2F90 + d%2F37.5 = 3.8

Multiply 90*37.5

3375*%28300-d%29%2F90 + 3375*d%2F37.5 = 3.8(3375)

cancel the denominator

37.5(300-d) + 90d = 12825

11250 - 37.5d + 90d = 12825

52.5d = 1575

d = 1575/52.5

d = 30 mi thru the mountains

Check this, find the distance on the plain

300-30 = 270 mi

Find the actual time at each speed

270/90 = 3 hrs

30/37.5 = .8 hrs

-----------------

total time: 3.8 hrs

7 0
3 years ago
On the grid, draw the graph of<br> y = 2x - 3<br> for values of x from -2 to 4<br> Q
Pie

Answer:

Plot these points:(-2,-7) (-1,-5) (0,-3) (1,-1) (2,1) (3,3) (4,5)

Step-by-step explanation:

You need to substitute your x values into the x of the equation y=2(3)-3 to find the y value...

3 0
3 years ago
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