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solong [7]
3 years ago
11

in parallelogram abcd diagonals ac and bd intersect at point l . If Al= x-2 and ac =3x-16 , then which of the following represen

ts the length of cl answer
Mathematics
1 answer:
TiliK225 [7]3 years ago
4 0

Answer:

The length of CI is 10 units.

Step-by-step explanation:

It is given that ABCD is a parallelogram and diagonals AC and BD intersect at point I.

The diagonals of a parallelogram bisect each other.

AI=CI

AC=AI+CI

AC=AI+AI                 [\because AI=CI]

AC=2AI

3x-16=2(x-2)

3x-16=2x-4

3x-2x=16-4

x=12

The value of x is 12.

CI=AI=x-2=12-2=10

Therefore the  length of CI is 10 units.

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\boxed{20(r + 3t)}

Step-by-step explanation:

20r + 60t

Factor out 20 from the expression.

20(r) + 20(3t)

Take 20 as common.

20(r + 3t)

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Is there any video related to this or can you explain how to do it
uranmaximum [27]

Angles ECD  and CEF add to 180

40+140 = 180

So that means we have EF parallel to CD (due to the same side interior angle theorem)

--------------

Angles BCE and ECD combine to 30+40 = 70, which is congruent to angle ABC = 70 as well.

In other words, this shows angle ABC = angle BCD. Both of these angles are alternate interior angles. Since they're congruent, they lead to AB being parallel to CD.

--------------

So far we have

AB || CD

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Using the transitive property, we can then link the two statements to say AB || EF. Think of a chain where CD is the common link. We go from AB to CD, then from CD to EF. So we can just take a single path from AB to EF.

It's like saying "P --> Q and Q --> R, therefore P --> R"

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