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Ann [662]
3 years ago
9

Will give brainliest, (404/4)x(2x2) to the power of 2.

Mathematics
1 answer:
Ganezh [65]3 years ago
7 0

Answer:

163216

Step-by-step explanation:

If it's the sign of multiplication

404/4=101

2*2=4*101=404^2=163216

or,

If it's x

(404/4)x(2x2)

(101)x(2x2)

101x (4x)^2

1616x^2

2611456

I am not sure if it's right

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Leona [35]
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3 years ago
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(a) Solve the following formula for b.
pav-90 [236]

Answer:

J Trump has to be a great day of school and I have a great

Step-by-step explanation:

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5 0
2 years ago
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
What is the product of 2x2 – 3xy + y2 and 2x – 4y?
Ganezh [65]

Answer:

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

Step-by-step explanation:

Given:

Product of 2x^2 – 3xy + y^2 and 2x – 4y

Product means multiplication

(2x^2 – 3xy + y^2) (2x – 4y)

Open the bracket

= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3

Simplify the like terms

= 4x^3 - 14x^2y + 14xy^2 - 4y^3

The answer is

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

6 0
4 years ago
Plssss help me it’s really important!!!
slavikrds [6]

Answer:

B

Step-by-step explanation:

Since ∠ E = ∠ F then the triangle is isosceles and DF = DE, that is

6x = x + 2y ( subtract x from both sides )

5x = 2y ( subtract 2y from both sides )

5x - 2y = 0 → (1)

and perimeter = 29, that is

6x x + 2y + 5x - y = 29 , simplifying

12x + y = 29 → (2)

Multiply (2) by 2

24x + 2y = 58 → (3)

Add (1) and (3) term by term to eliminate y, that is

29x = 58 ( divide both sides by 29 )

x = 2

Substitute x = 2 into (2) and evaluate for y

12(2) + y = 29

24 + y = 29 ( subtract 24 from both sides )

y = 5

Thus

FE = 5x - y = 5(2) - 5 = 10 - 5 = 5 → B

3 0
3 years ago
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