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2 years ago

Help me i actually need this asap...Only right answer ..No spammer.No wrong answer.

Mathematics

2 answers:

Leona [35]2 years ago

7 0

$\sqrt[3]{8} \: - \sqrt{3}$

katrin2010 [14]2 years ago

6 0

.............5b............

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HELP URGENT BRAINLIEST

nadya68 [22]

Given:

LMN is an equilateral triangle.

LM = LN = MN = 12 cm

To find:

The height of the triangle h.

Solution:

In a right angle triangle,

$\sin \theta=\dfrac{Opposite}{Hypotenuse}$

$\sin (60^\circ)=\dfrac{h}{12}$

$\dfrac{\sqrt{3}}{2}=\dfrac{h}{12}$

Multiply both sides by 12.

$\dfrac{\sqrt{3}}{2}\times 12=\dfrac{h}{12}\times 12$

$6\sqrt{3}=h$

Therefore, the height of the triangle is $6\sqrt{3}$ cm.

3 0

2 years ago

Find the length of CU, the triangles are similar.

Otrada [13]

Answer:

CU = 117

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{WC}{WU}$ = $\frac{CD}{UV}$

substituting in values to the ratios

$\frac{26}{36x-1}$ = $\frac{24}{132}$ ( cross- multiply )

24(36x - 1) = 3432 ( divide both sides by 24 )

36x - 1 = 143 ( add 1 to both sides )

36x = 144 ( divide both sides by 36 )

x = 4

CU = 36x - 1 - 26 = (36 × 4) - 27 = 144 - 27 = 117

3 0

3 years ago

What are two numbers that have a product of 12 and a sum of 5

pashok25 [27]

Answer:

there are no two numbers that have a product of 12 and a sum of 5 make sure that the question is correct

yo can find two numbers that have a product of 12 and a sum of 7 the answer is 3 and 4 .

Step-by-step explanation:

6 0

2 years ago

1. Which expression shows the distance on the number line between −14 and −5 ?

kiruha [24]

You can use this to help you.https://www.symbolab.com/

5 0

2 years ago

The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:

deff fn [24]

Step-by-step explanation:

Given equation of circle is,

${x}^{2} + {y}^{2} - 6y - 12 = 0 \\ by \: compairing \: it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f= - 6 \\ or \: f= - 3 \\ c = - 12$

again the another form of circle is,

${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0

3 years ago

Help me i actually need this asap...Only right answer ..​No spammer.No wrong answer.

Help me i actually need this asap...Only right answer ..No spammer.No wrong answer.