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Eva8 [605]
4 years ago
4

Master and his assistant working together can finish building a room in 15 days. How long would it take each of them to build th

e room working separately, if it is known that the master can finish it 16 days earlier than the assistant?
Mathematics
2 answers:
Alika [10]4 years ago
6 0

Answer:

The master takes 24 days and the assistant takes 40 days.

Step-by-step explanation:

Let y be the number of days the master takes to build the room and x the number of days the assistant takes.

Ten, working the fraction of the room they can individually build in a day:

1/ x + 1/y = 1/15.

Also  y = x - 16

Substituting for y in the first equation:

1/x + 1/ (x - 16) = 1/15

Multiply through by the LCD  15x(x - 16):

15(x - 16) + 15x =  x(x - 16)

15x + 15x - 240 = x^2 - 16x

x^2 - 16x - 30x + 240 = 0

x^2 - 46x + 240 = 0

(x  - 40)(x - 6) = 0

x = 6, 40.

Now , as y = x - 16 x must be 40, and y =  40 - 16 = 24 days.

So the assistant takes 40 days to build the room and the master takes  24 days.

Read more on Brainly.com - brainly.com/question/15633752#readmore

kupik [55]4 years ago
3 0

Answer:

The master takes 24 days and the assistant takes 40 days.

Step-by-step explanation:

Let y be the number of days the master takes to build the room and x the number of days the assistant takes.

Ten, working the fraction of the room they can individually build in a day:

1/ x + 1/y = 1/15.

Also  y = x - 16

Substituting for y in the first equation:

1/x + 1/ (x - 16) = 1/15

Multiply through by the LCD  15x(x - 16):

15(x - 16) + 15x =  x(x - 16)

15x + 15x - 240 = x^2 - 16x

x^2 - 16x - 30x + 240 = 0

x^2 - 46x + 240 = 0

(x  - 40)(x - 6) = 0

x = 6, 40.

Now , as y = x - 16 x must be 40, and y =  40 - 16 = 24 days.

So the assistant takes 40 days to build the room and the master takes  24 days.

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