Ask question

Ask question

All categories

Amiraneli [1.4K]

3 years ago

11

please help!!!!!!!. when opening doors for new construction, the following variables are specified. which of these variables is

quantative? (2 points). a) purpose of door: interior or exterior. b) width of door opening in inches. c) core of door: solid core or hollow core. d) color of door: white, oak, stain, natural, or ivory

1 answer:

vazorg [7]3 years ago

5 0

<span>When opening doors for new construction, then the width of door opening in inches will be a quantative vairable. Rest other options, i.e. purpose of door: interior or exterior, core of door: solid core or hollow core, color of door: white, oak, stain, natural, or ivory. </span>

You might be interested in

Need help with formula. Population of people is 5.3 per square mile and is 39 thousand square mile in size. What is the populati

VladimirAG [237]

Answer:

P = 5.3x = 206,700

Step-by-step explanation:

P = population

P = 5.3x, where x is the square miles

p = 5.3(39000) = 206,700

5 0

3 years ago

What is the mixed number to 53/12

Virty [35]

The mixed number is 4 5/12.

6 0

3 years ago

in 2006 ,the enrollment at jefferson high school was 1,200 students in 2012 the enrollment at jefferson high school was 1,650 st

Usimov [2.4K]

1650 - 1200 = 450
What percent is 450 of 1200?
y = 450/1200
y = 0.375
37.5% increase

3 0

3 years ago

Read 2 more answers

X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

cluponka [151]

Answer:

$x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

Step-by-step explanation:

I'm assuming the system is $\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.$ :

$x^2+y^2=2$

$x^2+(2x^2-3)^2=2$

$x^2+(4x^4-12x^2+9)=2$

$x^2+4x^4-12x^2+9=2$

$4x^4-11x^2+9=2$

$4x^4-11x^2+7=0$

$x^4-11x^2+28=0$

$(x^2-7)(x^2-4)=0$

$(4x^2-7)(x^2-1)=0$

$4x^2-7=0$

$4x^2=7$

$x^2=\frac{7}{4}$

$x=\pm\sqrt{\frac{7}{4}}$

$x^2-1=0$

$x^2=1$

$x=\pm1$

$y=2x^2-3$

$y=2(\pm\sqrt{\frac{7}{4}})^2-3$

$y=2({\frac{7}{4}})-3$

$y=\frac{7}{2}-3$

$y=\frac{1}{2}$

$y=2x^2-3$

$y=2(\pm1)^2-3$

$y=2(1)-3$

$y=2-3$

$y=-1$

Therefore, $x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}$ and $y=-1,\frac{1}{2}$

The ordered pair solutions are $(-\sqrt{\frac{7}{4}},0.5)$ , $(\sqrt{\frac{7}{4}},0.5)$ , $(-1,-1)$ , and $(1,-1)$ .

4 0

2 years ago

Find the perimeter of 3ft

myrzilka [38]

Answer:It would be 8ft ??

Step-by-step explanation: 3ft = 8ft

4 0

3 years ago