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zloy xaker [14]
3 years ago
8

What shape is this???

Mathematics
1 answer:
Vlad [161]3 years ago
6 0

Answer:

A parallelogram.

Step-by-step explanation:

See the 4 sides and the tilt? those are key features but what stands out is that they have 2 pairs of parallel sides. They never intersect.


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How do I factor this
melamori03 [73]
There is a factor of 10p in each term that is common, and thus, you can take them out of each term to yield 10p(p² - 196).
Now, 196 is a perfect square. That is, there is a real number that when multiplied by itself gives 196 (14).
Since p² - 14² is a difference of two squares, we can rewrite it as (p + 14)(p - 14).

So, our factored form is 10p(p + 14)(p - 14)
3 0
3 years ago
The function f(x)=x^2 -6x+3 is transformed such that g(x)=f(x-2). Find the vertex of g(x).
Lisa [10]

Answer:

g(x) = (x-2)^2 -6(x-2) +3

g(x) = x^2 -4x +4 -6x +12 +3

g(x) = x^2 -10 x +19

g(x) = x^2 -10 x + 25 +19 -25

g(x) = (x-5)^2 -6

y= (x-h)^2 -kk

Where h,k represent the vertex and we got:

(h,k)= (5,6)

(5,6)

Step-by-step explanation:

We have this original function given :

f(x) = x^2 -6x +3

And we want to find the vertex for this new function g(x) = f(x-2) and we have:

g(x) = (x-2)^2 -6(x-2) +3

And solving the square we got:

g(x) = x^2 -4x +4 -6x +12 +3

And adding similar terms we got:

g(x) = x^2 -10 x +19

Now we can complete the square like this:

g(x) = x^2 -10 x + 25 +19 -25

g(x) = (x-5)^2 -6

The general equation is given by:

y= (x-h)^2 -kk

Where h,k represent the vertex and we got:

(h,k)= (5,6)

(5,6)

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7 0
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