We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
Answer:
-392
Step-by-step explanation:
-56 x 7=-392
-392 / -56=7
GCF(13; 52) = 13
13 = 13 · 1
52 = 13 · 4
13 + 52 = 13 · 1 + 13 ·4 = 13·(1 + 4)
Used distributive property: a(b + c) = ab + ac
Answer: i d k
Step-by-step explanation:
