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kherson [118]
3 years ago
12

1_1/2 + 1_3/. find the sum

Mathematics
1 answer:
vesna_86 [32]3 years ago
8 0

Answer:

-1/5

Step-by-step explanation:

Your question is a little badly written . But if take it properly , The solution will be like :

1-0/5+1-3=-1-0/5=-1/5

Good luck ^^

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Differentiate x^2 e^x logx
zimovet [89]

Product rule:

\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)

=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}

Power rule:

\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x

The exponential function is its own derivative:

\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x

Assuming the base of \log x is e, its derivative is

\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x

But if you mean a logarithm of arbitrary base b, we have

y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}

\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}

So we end up with

2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x

=xe^x(2\log x+x\log x+1)

8 0
3 years ago
Evaluate g(x)=6x when x=-3,0, and 4 .
hram777 [196]

Answer:

-3 = -18

0 = 0

4 = 24

Step-by-step explanation:

-3... so 6(-3) equals -18 because a positive times a negative equals a negative

0... so 6 (0) equals 0 because anything multiplied by 0 equals 0

4... so 6 (4) equals 24

() means multiplied by so if it’s y(x) then that means y is multiplied by x :)

3 0
3 years ago
The perez family is researching the cost of keeping their dog at a kennel during an upcoming vacation . The local kennel allows
kogti [31]

Answer:

$15. :P ;-; XD

it's $15//

3 0
3 years ago
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marysya [2.9K]
Given that t<span>he function b(n) = 12n represents the number of baseballs b(n) that are needed for n games.

Then the number of baseballs needed for 15 games is given by b(n) = 12(15) = 180.</span>
8 0
3 years ago
Pls help me do this :']
JulijaS [17]

Answer:

ur mom

Step-by-step explanation:

7 0
2 years ago
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