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3 years ago

What is the correct substitution? evaluate. 3m when m = -9 and n = -2

Mathematics

1 answer:

Vinvika [58]3 years ago

8 0

Hi my name is Vanessa i'm Boribaby. I just wanted to let you know that answers A and C are the exact same thing.

I think I know your answer.... if any of your answers say 3(-9)(-2) then that is your answer.

Please know that the percentage of my answer is 50/50. I hope this help!!!! Good luck!!!!

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With what radius will a circle with a central angle

Vinil7 [7]

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Step-by-step explanation:

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3 years ago

Higher order thinking: Jeff finds some bugs. He finds 10 Fewer grasshoppers than crickets. He finds 5 fewer crickets than Lady b

Stells [14]

C - 10 = g
L - 5 = C

g = 5

then altogether he finds

40 bugs

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3 years ago

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Vladimir [108]

Answer:

120th caller

Step-by-step explanation:

120 is the common number by 40 and 30. trust me on this I'm really good at this subject in math.

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3 years ago

En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz

nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

= 180° - 72° - 64°

= 44°

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

= 180° - 90° - 72°

= 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

= 180° - 18° - 36°

= 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

= 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

= 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

= 180° - 14° - 54°

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

= 112° - 14°

= 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

4 0

3 years ago

In the figure, a square is inside another bigger square.

evablogger [386]

Answer:

Part 1) The length of the diagonal of the outside square is 9.9 units

Part 2) The length of the diagonal of the inside square is 7.1 units

Step-by-step explanation:

step 1

Find the length of the outside square

Let

x -----> the length of the outside square

c ----> the length of the inside square

we know that

$x=a+b=4+3=7\ units$

step 2

Find the length of the inside square

Applying the Pythagoras Theorem

$c^{2}= a^{2}+b^{2}$

substitute

$c^{2}= 4^{2}+3^{2}$

$c^{2}=25$

$c=5\ units$

step 3

Find the length of the diagonal of the outside square

To find the diagonal Apply the Pythagoras Theorem

Let

D -----> the length of the diagonal of the outside square

$D^{2}= x^{2}+x^{2}$

$D^{2}= 7^{2}+7^{2}$

$D^{2}=98$

$D=9.9\ units$

step 4

Find the length of the diagonal of the inside square

To find the diagonal Apply the Pythagoras Theorem

Let

d -----> the length of the diagonal of the inside square

$d^{2}= c^{2}+c^{2}$

$d^{2}= 5^{2}+5^{2}$

$d^{2}=50$

$d=7.1\ units$

7 0

3 years ago

Read 2 more answers