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Gnesinka [82]
3 years ago
15

Which of the following is an example of a syntax error?

Computers and Technology
1 answer:
Yuri [45]3 years ago
4 0

Answer:

misspelling a programming language word

Explanation:

Syntax error is the type of error in programming, when the programmer insert some symbol that is not present in directories or libraries, the programmer not followed the rules of that particular programming language that is understandable to compiler.

For example in C++, it is necessary to insert the semicolon (;) after each statement. If the programmer not insert the semicolon after each statement, the program will show the syntax error.

If the programmer use integer instead of int to assign datatype to the variable in C++, it will also leads to the syntax error. Because in C++ library, Integer is defined with the help of "int".

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what could a company do if it was using a commercial wan and a vulnerability appered thst allowed attackers
Radda [10]

Answer:

The answer is below

Explanation :

If a company was using a commercial WAN and a vulnerability appeared that allowed attackers find routing information and therefore be able to eavesdrop on corporate transmissions "It is expected that such a company should try to formulate and establish Virtual Private Networks between corporate sites.

This will ultimately lead to intercepted transmissions to be unreadable. Though such means have been seen as time-consuming."

4 0
3 years ago
company gives the following discount if you purchase a large amount of supply. Units Bought Discount 10 - 19 20% 20 - 49 30% 50
ratelena [41]

Answer:

In Python:

order = int(input("Order: "))

discount = 0

if(order >= 10 and order <20):

    discount = 0.20

elif(order >= 20 and order <50):

    discount = 0.30

elif(order >= 50 and order <100):

    discount = 0.35

elif(order >= 100):

    discount = 0.40

price = order * 4.1

discount = discount * price

print("With your order of "+str(order)+" items, the total value will be $"+str(round(price,2))+" with a discount of $"+str(round(discount,2))+" for a final price of $"+str(round((price-discount),2)))

Explanation:

This prompts the user for number of orders

order = int(input("Order: "))

This initializes the discount to 0

discount = 0

For orders between 10 and 19 (inclusive)

if(order >= 10 and order <20):

-----------discount is 20%

    discount = 0.20

For orders between 20 and 49 (inclusive)

elif(order >= 20 and order <50):

-----------discount is 30%

    discount = 0.30

For orders between 50 and 99 (inclusive)

elif(order >= 50 and order <100):

-----------discount is 35%

    discount = 0.35

For orders greater than 99

elif(order >= 100):

-----------discount is 40%

    discount = 0.40

This calculates the total price

price = order * 4.1

This calculates the pre discount

discount = discount * price

This prints the report

print("With your order of "+str(order)+" items, the total value will be $"+str(round(price,2))+" with a discount of $"+str(round(discount,2))+" for a final price of $"+str(round((price-discount),2)))

3 0
3 years ago
WILL MARK BRAIN LIST!
Tcecarenko [31]

Answer:

try D not sure

Explanation:

sorry if wrong happy if right!!!!!!

6 0
3 years ago
Read 2 more answers
During prereading, it is not important to pay attention to visual aids. please select the best answer from the choices provided
Nadusha1986 [10]
True Because the visual aids will provide better hand to eye coordination
7 0
2 years ago
Taking a suitable example in c language explain the of call by value and call by reference concepts.
Degger [83]

Answer: The difference between call by value and call by reference is that in call by value the actual parameters are passed into the function as arguments whereas in call by reference the address of the variables are sent as parameters.

Explanation:

Some examples are:

call by value

#include <stdio.h>  

void swap(int, int);

int main()

{  int a = 10, b= 20;

 swap(a, b);

 printf("a: %d, b: %d\n", a, b);

}  

void swap(int c, int d)

{

 int t;

 t = c; c = d; d = t;

}  

OUTPUT

a: 10, b: 20

The value of a and b remain unchanged as the values are local

//call by reference

#include <stdio.h>

 void swap(int*, int*);

 int main()

{

 int a = 10, b = 20;

 swap(&a, &b);   //passing the address

 printf("a: %d, b: %d\n", a, b);

}

void swap(int *c, int *d)

{

 int t;

 t = *c; *c = *d; *d = t;

}

OUTPUT

a: 20, b: 10

due to dereferencing by the pointer the value  can be changed which is call by reference

8 0
4 years ago
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