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IgorC [24]
3 years ago
8

At the start of the school year, Brianna’s history teacher announces that students’ final grades will be weighted based on how t

hey do in three categories: exams (60 percent), final presentation (30 percent), and class participation (10 percent). Which strategy would most likely help Brianna get the best grade? spending more time studying for exams than creating the final presentation splitting her time evenly between studying for exams and creating the final presentation concentrating on creating the final presentation and speaking up in class working hard at participating in class and studying for exams
Computers and Technology
2 answers:
Musya8 [376]3 years ago
6 0

Answer:

A

Explanation:

Dennis_Churaev [7]3 years ago
5 0

Answer:

it is A

Explanation:

did on edge test

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Which of the following is not a technology that can be used to conserve resources?
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Write a method called findNames that meets the following specs: It takes two arguments: a list of strings, allNames, and a strin
Anna11 [10]

Answer:

public class Solution {

   public static void main(String args[]) {

       String[] allNames = new String[]{"Bob Smith", "Elroy Jetson", "Christina Johnson", "Rachael Baker", "cHRis", "Chris Conly"};

       String searchString = "cHRis";

       

       findNames(allNames, searchString);

   }

   

   public static void findNames(String[] listOfName, String nameToFind){

       ArrayList<String> resultName = new ArrayList<String>();

       

       for(String name : listOfName){

           if (name.toLowerCase().contains(nameToFind.toLowerCase())){

               resultName.add(name);

           }

       }

       

       for(String result : resultName){

           System.out.println(result);

       }

   }

}

Explanation:

The class was created called Solution. The second line define the main function. Inside the main function; we initialized and assign an array called allNames to hold the list of all name. Then a String called searchString was also defined. The searchString is the string to search for in each element of allNames array. The two variables (allNames and searchString) are passed as argument to the findNames method when it is called.

The method findNames is defined and it accept two parameters, an array containing list of names and the name to search for.

Inside the findNames method, we initialized and assigned an ArrayList called resultName. The resultName variable is to hold list of element found that contain the searchString.

The first for-loop goes through the elements in the allNames array and compare it with the searchString. If any element is found containing the searchString; it is added to the resultName variable.

The second for-loop goes through the elements of the resultName array and output it. The output is empty if no element was found added to the resultName variable.

During comparison, the both string were converted to lower case before the comparison because same lowercase character does not equal same uppercase character. For instance 'A' is not same as 'a'.

8 0
2 years ago
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