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LuckyWell [14K]
3 years ago
7

Write an equation of the line that is parallel to y = 1/2 x + 3 and passes through the point (10, -5). A) y = 2x - 15 B) y = -2x

+ 15 C) y = - 1 2 x D) y = 1 2 x - 10
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

The equation of this line is D) y = 1/2x - 10

Step-by-step explanation:

In order to find this, we need to first find the slope. The slope of the equation will match the line it is parallel to. Since the first line has a slope of 1/2 (the coefficient of x), we know our new line will too. Now that we have that information start with the basic form of point-slope form.

y - y1 = m(x - x1)

Now put the slope in for m and the point in for (x1, y1)

y + 5 = 1/2(x - 10)

Now solve the equation for y.

y + 5 = 1/2x - 5

y = 1/2x - 10


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Here we're given
p=0.10  [ success = defective ]
n=3

(a) x=0
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,0)0.1^0(1-0.1)^{3-0}
=1(1)(0.729)
=0.729

(b) x=2
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,2)0.1^2(1-0.1)^{3-2}
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(c) x ≥ 2
P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}
=P(2)+P(3)
=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}
=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}
=3(0.01)(0.9)+1(0.001)1
=0.027+0.001
=0.028


8 0
3 years ago
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Sunny_sXe [5.5K]

The answer is 7.

Look at the x=8 and then look up the y-value.

The graph passes (8,7) so therefore when x = 8 the y is 7

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Rearrange 3x - y = 4 into this form ( add y to both sides )

3x = y + 4 ( subtract 4 from both sides )

3x - 4 = y OR y = 3x - 4 → a

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