Try and use the web math papa it’ll give you the answer you needed
Answer:
a) Q1= 144.10
Median = 150
Q3=155.90
b) The 99 percentile would be:
And represent a value who accumulate 99% of the values below
Step-by-step explanation:
Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:
Where and
Part a
Lets begin with the first quartile:
(a)
(b)
We can find the quantile in the normal standard distribution and we got z=-0.674.
And we can apply the z score formula and we got:
And if we solve for a we got
The median for this case is the mean
For the third quartile we find the quantile who accumulate 0.75 of the area below and we got z=0.674 and we got:
Part b
We can find the quantile in the normal standard distribution who accumulate 0.99 of the area below and we got z=2.33.
And we can apply the z score formula and we got:
And if we solve for a we got
And represent a value who accumulate 99% of the values below
Answer:
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4 × ( x + 4 ) = 3 × ( 3 + 5 )
4 × ( x + 4 ) = 3 × 8
Divide both sides by 4
x + 4 = 3 × 2
x + 4 = 6
Subtract both sides 4
x = 2
Answer:
g(x)= 4x/5 + 8/5
Step-by-step explanation:
rewrite the equation as: -5y+2= -4x-6
move all terms not containing y to y=the right side of the equation
subtract 2 from both sides of the equation: -5y=-4x-6-2
subtract 2 from-6: -5y=-4x-8
divide each side by -5 and simplify: -5y=-4x-8 by -5
-5y÷-5 = -4x÷-5 + -8÷-5
now cancel the common factor of -5
divide y by 1: y= -4x/-5+ -8/-5
divide the negative to get the positives: y= (4)x/5 + -8/-5
y= 4x/5 +8/5
I hope this helped sorry if it wasn't what you were looking for.