The fact for Dons second array is that all he did was divide the second array in half.(4×7=28). (2×7=14). ( 28÷2=14). Hopefully that made sense!!!!!
Use the information to write the dimensions of each rectangle in terms of w, the width of the 1st one.
1st rectangle;
l = 2w
w = 2
2nd rectangle:
w = w
l = 2w + 4
If the area of the 2nd rectangle is 70 square meters, you will use the area formula to write an equation that you will solve using the factoring.
A = lw
70 = w(2w + 4)
70 = 2w^2 + 4w
0 = 2w^2 + 4w -70
0 = 2 (w^2 +2w - 35)
0 = 2 (w + 7) (w - 5)
To get zero, the width would need to be -7 or 5. Because it is a distance, it has to be 5 meters.
The width of both rectangles is 5 meters.
9189.15 ft (this is the answer and I have not rounded it)
Add all the integers together and then divide by 10 because that’s how many numbers you’re adding.
