Answer:
0.80+/- 0.016
(0.784, 0.816)
The 95% confidence interval on the proportion of people who regularly have a dental checkup is = (0.784, 0.816)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
p+/-z√(p(1-p)/n)
Given that;
Proportion p = 2000/2500 = 0.80
Number of samples n = 2500
Confidence interval = 95%
z-value(at 95% confidence) = 1.96
Substituting the values we have;
0.80+/- 1.96√(0.80(1-0.80)/2500)
0.80+/- 1.96√(0.000064)
0.80+/- 0.01568
0.80+/- 0.016
(0.784, 0.816)
The 95% confidence interval on the proportion of people who regularly have a dental checkup is = (0.784, 0.816)
