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suter [353]
3 years ago
11

So what is this 6t + 4 s-2​

Mathematics
1 answer:
sesenic [268]3 years ago
5 0
The answer would be S+6t+2
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A is the answer to your question
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Evaluate x-(-y)x−(−y)x, minus, left parenthesis, minus, y, right parenthesis where x = -2.31x=−2.31x, equals, minus, 2, point, 3
Angelina_Jolie [31]

Step-by-step explanation:

x-(-y)=x+y\\\\\text{substitute}\ x=-2.31,\ y=5.9:\\\\-2.31+5.9=5.9+(-2.31)=5.9-2.31=5.90-2.31=3.59

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A particle is moving with the given data. Find the position of the particle. a(t) = t2 − 3t + 9, s(0) = 0, s(1) = 20
sertanlavr [38]

Answer:

s(t) = \frac{t^4}{12}-\frac{3t^3}{6}+\frac{9t^2}{2} +15.91667t

Step-by-step explanation:

Integrating the expression that describes the acceleration of the particle gives us an expression for its velocity. Integrating the expression for its velocity, gives us the expression for its position:

a(t) = t^2-3t+9\\\int{a(t)} \, dt=v(t) = \frac{t^3}{3}-\frac{3t^2}{2}+9t +A\\\int{v(t)} \, dt=s(t) = \frac{t^4}{12}-\frac{3t^3}{6}+\frac{9t^2}{2} +At+B

Use the given values s(0) = 0 and s(s) = 20 to find the constants A and B:

s(0) =0= 0-0-0 +A*0+B\\B=0\\ s(1) =20= \frac{1^4}{12}-\frac{3*1^3}{6}+\frac{9*1^2}{2} +A*1+0\\ A=15.91667\\\\s(t) = \frac{t^4}{12}-\frac{3t^3}{6}+\frac{9t^2}{2} +15.91667t

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4 years ago
Solve x2 + 6x = 7 by completing the square. Which is the solution set of the equation?
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3 years ago
What is monomial, binomial, and trinomial?
lozanna [386]

Answer:

monomial—A polynomial with exactly one term.

binomial— A polynomial with exactly two terms.

trinomial—A polynomial with exactly three terms.

Notice the roots: poly– means many.

Step-by-step explanation:

Hope it helps!!

6 0
3 years ago
Read 2 more answers
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