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2 years ago

Write 7x10^-8 in standard form

Mathematics

2 answers:

dexar [7]2 years ago

8 0

Hey there! I'm happy to help!

Standard form is just writing this without the multiplication sign. If you multiply a number by 10 to a negative number, \you take the number in the negative exponent and move the decimal to the left that many times. In our case, we move it to the left 8 times.

If we move the decimal to the left 8 times, we have 0.00000007.

I hope that this helps! :D

attashe74 [19]2 years ago

6 0

Answer:

The answer would be 0.00000007

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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andre [41]

Check the picture below. So, more or less looks like so.

notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.

Also notice, the "c" distance from the center to either foci, is just 5 units.

$\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{{{ a }}^2+{{ b }}^2}
\end{cases}\\\\
-------------------------------\\\\$

$\bf \begin{cases}
h=0\\
k=0\\
a=4\\
c=5
\end{cases}\implies \cfrac{(y-{{ 0}})^2}{{{ 4}}^2}-\cfrac{(x-{{ 0}})^2}{{{ b}}^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{b^2}=1
\\\\\\
c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\\\\\\
\sqrt{5^2-4^2}=b\implies \boxed{3=b}
\\\\\\
\cfrac{y^2}{16}-\cfrac{x^2}{3^2}=1\implies \boxed{\cfrac{y^2}{16}-\cfrac{x^2}{9}=1}$

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3 years ago

What is the slope-intercept equation of the line below?

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Answer:

There is no image.

Step-by-step explanation:

Can you add a image or something because You did not give a "line below"

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