Answer:
3x-6
Step-by-step explanation:
Answer:
The F-statistic used to test the hypothesis that the miles per gallon for each fuel are the same is 4.07.
Step-by-step explanation:
There are four treatments in the data given, i.e. k = 4.
Total number of observations, n = 12.
Note: degrees of freedom is denoted as df.
For treatment, the degrees of freedom = k-1 = 4-1 =3 df.
The total degrees of freedom = n-1 = 12-1 = 11 df.
The error in degrees of freedom = df (total) - df(treatment)
The error in degrees of freedom = 11 - 3 = 8 df
At α = 0.05 level,from the F table, the F-statistic with (3 , 8)df is 4.07.
Therefore, the F-statistic used to test the hypothesis that the miles per gallon for each fuel are the same is 4.07.
Answer:
x = 5
Step-by-step explanation:
√(2x − 1) + 2 = x
√(2x − 1) = x − 2
2x − 1 = (x − 2)²
2x − 1 = x² − 4x + 4
0 = x² − 6x + 5
0 = (x − 1) (x − 5)
x = 1 or 5
Check for extraneous solutions.
√(2(1) − 1) + 2 = 1
√(1) + 2 = 1
3 = 1
No solution
√(2(5) − 1) + 2 = 5
√(9) + 2 = 5
5 = 5
x = 5
Answer: t-half = ln(2) / λ ≈ 0.693 / λExplanation:The question is incomplete, so I did some research and found the complete question in internet.
The complete question is:
Suppose a radioactive sample initially contains
N0unstable nuclei. These nuclei will decay into stable
nuclei, and as they do, the number of unstable nuclei that remain,
N(t), will decrease with time. Although there is
no way for us to predict exactly when any one nucleus will decay,
we can write down an expression for the total number of unstable
nuclei that remain after a time t:
N(t)=No e−λt,
where λ is known as the decay constant. Note
that at t=0, N(t)=No, the
original number of unstable nuclei. N(t)
decreases exponentially with time, and as t approaches
infinity, the number of unstable nuclei that remain approaches
zero.
Part (A) Since at t=0,
N(t)=No, and at t=∞,
N(t)=0, there must be some time between zero and
infinity at which exactly half of the original number of nuclei
remain. Find an expression for this time, t half.
Express your answer in terms of N0 and/or
λ.
Answer:
1) Equation given:
← I used α instead of λ just for editing facility..
Where No is the initial number of nuclei.
2) Half of the initial number of nuclei:
N (t-half) = No / 2So, replace in the given equation:
3) Solving for α (remember α is λ)
αt ≈ 0.693
⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ