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3 years ago

For what value of a do the lines 5x–2y=3 and x+y=a intersect at a point on the y-axis?

Mathematics

1 answer:

inna [77]3 years ago

5 0

Answer:

a = -3/2

Step-by-step explanation:

You can set x=0 and solve for y to find the y-intercept in each case.

first equation: y-intercept = -3/2

second equation: y-intercept = a

To make these equal, we must have ...

a = -3/2

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What is 6x(13-6) =7 squared?

Novay_Z [31]

6 × (13 - 6) = 42, not 7, but 7² is 49 and 42² is 1,764.
I hope this helps!

4 0

4 years ago

Read 2 more answers

If f(x)= x^1/2 - x and g(x)= 2x^3 - x^1/2 - x, find f(x) - g(x)

Pavlova-9 [17]

Answer:

$-2x^3+2x^{1/2}$

Step-by-step explanation:

First, you have to substitute both functions into the equation to get:

$f(x)-g(x) = (x^{1/2}-x) - (2x^3-x^{1/2}-x)$

Then, you distribute the negative sign in front of g(x) to get:

$= x^{1/2} - x -2x^3+x^{1/2}+x$

And finally, you add/subtract the x's that have the same power to get:

$=-2x^3+2x^{1/2}$

3 0

3 years ago

Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu

dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

$d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\$ Substituting the values

$d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\$

So the total distance travelled is 1031 feet.

4 0

3 years ago

DUE RIGHT NOW!!!!! PLEASE HELP!!!!!

elixir [45]

Gfurknegwuwn nakwubwkw. Jahsken

6 0

3 years ago

Forty five percent of middle schools have a horse as a mascot. If there are 420 middle schools how many have a horse as a mascot

allochka39001 [22]

189
Because you have to turn it into a percentage in order to know how many per 1 percent. So multiply 420 by 100 and get 4.2 then you multiply it by 45 and you get 189 so 179 schools have a horse mascot

3 0

3 years ago